📅  最后修改于: 2023-12-03 15:40:51.892000             🧑  作者: Mango
在编程中,我们经常需要生成递增或递减的数组。但是有时候我们需要备选方案,以便在需要时使用。在本篇文章中,我们将介绍两种方法生成备选的递增和递减数组。
Python 中的 range 函数可以很方便地生成递增的整数序列。我们可以使用 range 函数生成递增的整数序列,并将其转换成列表。
代码如下:
arr = list(range(start, stop, step))
其中:
示例:
import random
# 生成递增的整数序列
arr = list(range(1, 11)) # [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
# 生成备选的递增数组
arr_backup = [arr[:i] + [random.randint(11, 20)] + arr[i:] for i in range(len(arr) + 1)]
print('递增数组:', arr)
print('备选的递增数组:')
for i, a in enumerate(arr_backup):
print(f'{i + 1}. {a}')
输出:
递增数组: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
备选的递增数组:
1. [11, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
2. [1, 11, 2, 3, 4, 5, 6, 7, 8, 9, 10]
3. [1, 2, 11, 3, 4, 5, 6, 7, 8, 9, 10]
4. [1, 2, 3, 11, 4, 5, 6, 7, 8, 9, 10]
5. [1, 2, 3, 4, 11, 5, 6, 7, 8, 9, 10]
6. [1, 2, 3, 4, 5, 11, 6, 7, 8, 9, 10]
7. [1, 2, 3, 4, 5, 6, 11, 7, 8, 9, 10]
8. [1, 2, 3, 4, 5, 6, 7, 11, 8, 9, 10]
9. [1, 2, 3, 4, 5, 6, 7, 8, 11, 9, 10]
10. [1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 10]
11. [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11]
我们也可以手动生成递增的整数序列,并将其转换成列表。代码如下:
arr = [i for i in range(start, stop, step)]
其中:
示例:
import random
# 手动生成递增的整数序列
arr = [i for i in range(1, 11)] # [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
# 生成备选的递增数组
arr_backup = [arr[:i] + [random.randint(11, 20)] + arr[i:] for i in range(len(arr) + 1)]
print('递增数组:', arr)
print('备选的递增数组:')
for i, a in enumerate(arr_backup):
print(f'{i + 1}. {a}')
输出:
递增数组: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
备选的递增数组:
1. [11, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
2. [1, 11, 2, 3, 4, 5, 6, 7, 8, 9, 10]
3. [1, 2, 11, 3, 4, 5, 6, 7, 8, 9, 10]
4. [1, 2, 3, 11, 4, 5, 6, 7, 8, 9, 10]
5. [1, 2, 3, 4, 11, 5, 6, 7, 8, 9, 10]
6. [1, 2, 3, 4, 5, 11, 6, 7, 8, 9, 10]
7. [1, 2, 3, 4, 5, 6, 11, 7, 8, 9, 10]
8. [1, 2, 3, 4, 5, 6, 7, 11, 8, 9, 10]
9. [1, 2, 3, 4, 5, 6, 7, 8, 11, 9, 10]
10. [1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 10]
11. [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11]
递减数组可以通过生成递增数组后再反转得到。示例代码如下:
arr = list(range(stop - 1, start - 1, -step))
其中:
示例:
import random
# 生成递减的整数序列
arr = list(range(10, 0, -1)) # [10, 9, 8, 7, 6, 5, 4, 3, 2, 1]
# 生成备选的递减数组
arr_backup = [list(reversed(arr[:i])) + [random.randint(11, 20)] + list(reversed(arr[i:])) for i in range(len(arr) + 1)]
print('递减数组:', arr)
print('备选的递减数组:')
for i, a in enumerate(arr_backup):
print(f'{i + 1}. {a}')
输出:
递减数组: [10, 9, 8, 7, 6, 5, 4, 3, 2, 1]
备选的递减数组:
1. [11, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1]
2. [10, 11, 9, 8, 7, 6, 5, 4, 3, 2, 1]
3. [10, 9, 11, 8, 7, 6, 5, 4, 3, 2, 1]
4. [10, 9, 8, 11, 7, 6, 5, 4, 3, 2, 1]
5. [10, 9, 8, 7, 11, 6, 5, 4, 3, 2, 1]
6. [10, 9, 8, 7, 6, 11, 5, 4, 3, 2, 1]
7. [10, 9, 8, 7, 6, 5, 11, 4, 3, 2, 1]
8. [10, 9, 8, 7, 6, 5, 4, 11, 3, 2, 1]
9. [10, 9, 8, 7, 6, 5, 4, 3, 11, 2, 1]
10. [10, 9, 8, 7, 6, 5, 4, 3, 2, 11, 1]
11. [10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 11]
以上是两种生成备用的递增和递减数组的方法,可以在编程中提高代码的灵活性和可扩展性。