Java中的字符.isIdentifierIgnorable() 和示例
- Java.lang。 字符.isIdentifierIgnorable(char ch)是Java中的一个内置方法,用于确定指定字符是否应被视为Java标识符或 Unicode 标识符中的可忽略字符。
在Java标识符或 Unicode 标识符中可以忽略以下 Unicode字符:
- 非空白的 ISO 控制字符
- '\u0000' 到 '\u0008'
- '\u000E' 到 '\u001B'
- '\u007F' 到 '\u009F'
- 所有具有 FORMAT 通用类别值的字符
句法:
public static boolean isIdentifierIgnorable(char ch)
参数:参数ch是字符数据类型,指的是要测试的字符。
返回值:如果字符是可以是Java或 Unicode 标识符的一部分的可忽略控制字符,则此方法返回 true,否则返回 false。
下面的程序说明了字符.isIdentifierIgnorable(char ch) 方法:
方案一:
// Java program to illustrate // Character.isIdentifierIgnorable(char ch) method import java.lang.*; public class gfg { public static void main(String[] args) { // Creates 2 character primitives c1, c2 and assigning values char c1='\u0000', c2= '9'; // Assigns isIdentifierIgnorable results of // c1, c2 to boolean primitives boolean bool1 = Character.isIdentifierIgnorable(c1); boolean bool2 = Character.isIdentifierIgnorable(c2); String str1 = "c1 is an ignorable control character is " + bool1; String str2 = "c2 is an ignorable control character is " + bool2; System.out.println( str1 ); System.out.println( str2 ); } }
输出:c1 is an ignorable control character is true c2 is an ignorable control character is false
方案二:
import java.lang.*; public class gfg { public static void main(String[] args) { // Create 2 character primitives c1, c2 and assigning values char c1='\u000E', c2= '8'; // Assigns isIdentifierIgnorable results of // c1, c2 to boolean primitives boolean bool1 = Character.isIdentifierIgnorable(c1); boolean bool2 = Character.isIdentifierIgnorable(c2); String str1 = "c1 is an ignorable control character is " + bool1; String str2 = "c2 is an ignorable control character is " + bool2; System.out.println( str1 ); System.out.println( str2 ); } }
输出:c1 is an ignorable control character is true c2 is an ignorable control character is false
- 非空白的 ISO 控制字符
- Java.lang。 字符.isIdentifierIgnorable(int codePoint)在所有方面都类似于前面的方法。
句法:
public static boolean isIdentifierIgnorable(int codePoint)
参数:该函数接受一个整数数据类型的参数 codePoint,它指定要测试的字符(Unicode 代码点)。
返回值:如果字符是可以是Java或 Unicode 标识符的一部分的可忽略控制字符,则此方法返回 true,否则返回 false。
下面的程序说明了字符.isIdentifierIgnorable(int codepoint) 方法:
方案一:// Java program to demonstrate // the Character.isIdentifierIgnorable(int codepoint) method import java.lang.*; public class gfg { public static void main(String[] args) { // Integer primitives c1, c2 int c1 = 0x019f, c2 = 0x1abc; // Assign isIdentifierIgnorable results of cp1, cp2 // to boolean primitives bool1, bool2 boolean bool1 = Character.isIdentifierIgnorable(c1); boolean bool2 = Character.isIdentifierIgnorable(c2); // Print bool1, bool2 values System.out.println( "c1 is an ignorable control character?"+ " ans is "+bool1); System.out.println( "c2 is an ignorable control character?"+ " ans is "+bool2); } }
输出:c1 is an ignorable control character? ans is false c2 is an ignorable control character? ans is false
方案二:
// Java program to demonstrate // the Character.isIdentifierIgnorable(int codepoint) method import java.lang.*; public class gfg { public static void main(String[] args) { // Integer primitives c1, c2 int c1 = 0x119f, c2 = 0x0abc; // Assign isIdentifierIgnorable results of cp1, cp2 // to boolean primitives bool1, bool2 boolean bool1 = Character.isIdentifierIgnorable(c1); boolean bool2 = Character.isIdentifierIgnorable(c2); // Print bool1, bool2 values System.out.println( "c1 is an ignorable control character?"+ " ans is "+bool1); System.out.println( "c2 is an ignorable control character?"+ " ans is "+bool2); } }
输出:c1 is an ignorable control character? ans is false c2 is an ignorable control character? ans is false
参考: https: Java/lang/ 字符.html#isIdentifierIgnorable(char)