SymPy | Python中的 Permutation.is_odd()

Permutation.is_odd() ：is_odd()是一个 sympy Python库函数，用于检查排列是否为奇数。

Syntax : sympy.combinatorics.permutations.Permutation.is_odd()

Return : true – if the permutation is odd; otherwise false

代码 #1：is_odd() 示例

# Python code explaining
# SymPy.Permutation.is_odd()
  
# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation
  
# Using from sympy.combinatorics.permutations.Permutation.is_odd() method 
  
# creating Permutation
a = Permutation([[2, 0], [3, 1]])
  
b = Permutation([1, 3, 5, 4, 2, 0])
  
  
print ("Permutation a - is_odd form : ", a.is_odd)
print ("Permutation b - is_odd form : ", b.is_odd)

输出 ：

Permutation a – is_odd form : False
Permutation b – is_odd form : True

代码 #2 : is_odd() 示例– 2D 排列

# Python code explaining
# SymPy.Permutation.is_odd()
  
# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation
  
# Using from sympy.combinatorics.permutations.Permutation.is_odd() method 
  
# creating Permutation
a = Permutation([[2, 4, 0], 
                 [3, 1, 2],
                 [1, 5, 6]])
  
  
print ("Permutation a - is_odd form : ", a.is_odd)

输出 ：

Permutation a – is_odd form : False