Java中的 AbstractList get() 方法及示例
Java.util.AbstractList类的get()方法用于返回该列表中指定位置的元素。
句法:
public abstract E get(int index)
参数:该方法将元素的索引作为参数,即要返回的元素。
返回值:此方法返回此列表中指定位置的元素。
异常:如果索引超出范围 (index = size()),此方法将引发IndexOutOfBoundsException 。
下面是说明get()方法的示例。
示例 1:
// Java program to demonstrate
// get() method
// for Integer value
import java.util.*;
public class GFG1 {
public static void main(String[] argv)
throws Exception
{
try {
// Creating object of AbstractList
AbstractList
arrlist1 = new ArrayList();
// Populating arrlist1
arrlist1.add(10);
arrlist1.add(20);
arrlist1.add(30);
arrlist1.add(40);
arrlist1.add(50);
// print arrlist1
System.out.println("ArrayListlist : "
+ arrlist1);
// getting the value at the index 3
// using get() method
int value = arrlist1.get(3);
// print the value
System.out.println("Element at index 3 : "
+ value);
}
catch (IndexOutOfBoundsException e) {
System.out.println("Exception thrown : " + e);
}
}
}
输出:
ArrayListlist : [10, 20, 30, 40, 50]
Element at index 3 : 40
示例 2:
// Java program to demonstrate
// get() method
// for IndexOutOfBoundsException
import java.util.*;
public class GFG1 {
public static void main(String[] argv)
throws Exception
{
try {
// Creating object of AbstractList
AbstractList
arrlist1 = new ArrayList();
// Populating arrlist1
arrlist1.add(10);
arrlist1.add(20);
arrlist1.add(30);
arrlist1.add(40);
arrlist1.add(50);
// print arrlist1
System.out.println("ArrayListlist : "
+ arrlist1);
// getting the value at the index 7
// using get() method
System.out.println("\nTrying to get "
+ "the element from out"
+ " of range index ");
int value = arrlist1.get(7);
// print the value
System.out.println("Element at index 7 : "
+ value);
}
catch (IndexOutOfBoundsException e) {
System.out.println("Exception thrown : " + e);
}
}
}
输出:
ArrayListlist : [10, 20, 30, 40, 50]
Trying to get the element from out of range index
Exception thrown : java.lang.IndexOutOfBoundsException: Index: 7, Size: 5