📜  Java中的流排序()

📅  最后修改于: 2022-05-13 01:55:37.506000             🧑  作者: Mango

Java中的流排序()

Stream sorted()返回一个由该流的元素组成的流,按照自然顺序排序。对于有序流,排序方法是稳定的,但对于无序流,不能保证稳定性。它是一个有状态的中间操作,即在处理新元素时,它可以合并来自先前看到的元素的状态。

句法 :

Stream sorted()

Where, Stream is an interface and T
is the type of stream elements.

异常:如果此流的元素不是 Comparable,则在执行终端操作时可能会抛出Java.lang.ClassCastException

下面给出了一些示例,以更好地理解该函数的实现。

示例 1:

// Implementation of Stream.sorted()
// to get a stream of elements
// sorted in their natural order
import java.util.*;
  
class GFG {
  
    // Driver code
    public static void main(String[] args)
    {
  
        // Creating a list of integers
        List list = Arrays.asList(-9, -18, 0, 25, 4);
  
        System.out.println("The sorted stream is : ");
  
        // displaying the stream with elements
        // sorted in natural order
        list.stream().sorted().forEach(System.out::println);
    }
}
输出:
The sorted stream is : 
-18
-9
0
4
25

示例 2:

// Implementation of Stream.sorted()
// to get a stream of elements
// sorted in their natural order
import java.util.*;
  
class GFG {
  
    // Driver code
    public static void main(String[] args)
    {
  
        // Creating a list of strings
        List list = Arrays.asList("Geeks", "for",
                     "GeeksQuiz", "GeeksforGeeks", "GFG");
  
        System.out.println("The sorted stream is : ");
  
        // displaying the stream with elements
        // sorted in their natural order
        list.stream().sorted().forEach(System.out::println);
    }
}
输出:
The sorted stream is : 
GFG
Geeks
GeeksQuiz
GeeksforGeeks
for

示例 3:

// Using stream sorted to sort a stream
// of user defined class objects
import java.util.*;
  
class Point
{
    Integer x, y;
    Point(Integer x, Integer y) {
        this.x = x;
        this.y = y;
    }
      
    public String toString() { 
        return this.x + ", "+ this.y;
    } 
}
  
class GFG
{
    public static void main(String[] args)
    {
  
        List aList = new ArrayList<>();
        aList.add(new Point(10, 20));
        aList.add(new Point(5, 10));
        aList.add(new Point(1, 100));
        aList.add(new Point(50, 2000));
  
        // displaying the stream with elements
        // sorted according to x coordinate
        aList.stream()
        .sorted((p1, p2)->p1.x.compareTo(p2.x))
        .forEach(System.out::println);
    }
}
输出:
1, 100
5, 10
10, 20
50, 2000