给定兔子和鸽子的腿和头的总数。任务是计算兔子和鸽子的数量。
例子:
Input: Heads = 200, Legs = 540
Output: Rabbits = 70, Pigeons = 130
Input: Heads = 100, Legs = 300
Output: Rabbits = 50, Pigeons = 50
Let the total no. of Heads = 200 and Legs = 540.
Let the number of Head and Legs of Rabbits = X and that of Pigeons = Y.
so,
X + Y = 200 ..equation 1 (no. of the heads of a rabbit and a pigeon = total no. of heads)
(As both of them has 1 head)
4X + 2Y = 540 …equation 2 (no. of the legs of the rabbit and a pigeon = total no. of legs)
(Rabbit have 4 legs and pigeons have 2 legs)
Now, solving equation 1 and 2 we get,
4X = 540 – 2Y
4X = 540 – 2 * (200 – X)
4X = 540 – 400 + 2X
2X = 140 => X = 70
X = 70 and Y = 130.
hence, Rabbits = 70 and Pigeons = 130
下面是上述方法的实现:
C++
// C++ implementation of above approach
#include
using namespace std;
// Function that calculates Rabbits
int countRabbits(int Heads, int Legs)
{
int count = 0;
count = (Legs)-2 * (Heads);
count = count / 2;
return count;
}
// Driver code
int main()
{
int Heads = 100, Legs = 300;
int Rabbits = countRabbits(Heads, Legs);
cout << "Rabbits = " << Rabbits << endl;
cout << "Pigeons = " << Heads - Rabbits << endl;
return 0;
}
Java
// Java implementation of above approach
import java.util.*;
import java.lang.*;
class GFG
{
// Function that calculates Rabbits
static int countRabbits(int Heads,
int Legs)
{
int count = 0;
count = (Legs) - 2 * (Heads);
count = count / 2;
return count;
}
// Driver code
public static void main(String args[])
{
int Heads = 100, Legs = 300;
int Rabbits = countRabbits(Heads, Legs);
System.out.println("Rabbits = " +
Rabbits);
System.out.println("Pigeons = " +
(Heads - Rabbits));
}
}
// This code is contributed
// by Akanksha Rai(Abby_akku)
Python3
# Python 3 implementation of above approach
# Function that calculates Rabbits
def countRabbits(Heads, Legs):
count = 0
count = (Legs) - 2 * (Heads)
count = count / 2
return count
# Driver code
if __name__ == '__main__':
Heads = 100
Legs = 300
Rabbits = countRabbits(Heads, Legs)
print("Rabbits =", Rabbits)
print("Pigeons =", Heads - Rabbits)
# This code is contributed
# by Surendra_Gangwar
C#
// C# implementation of above approach
using System;
class GFG
{
// Function that calculates Rabbits
static int countRabbits(int Heads,
int Legs)
{
int count = 0;
count = (Legs) - 2 * (Heads);
count = count / 2;
return count;
}
// Driver code
public static void Main()
{
int Heads = 100, Legs = 300;
int Rabbits = countRabbits(Heads, Legs);
Console.WriteLine("Rabbits = " +
Rabbits);
Console.WriteLine("Pigeons = " +
(Heads - Rabbits));
}
}
// This code is contributed
// by Akanksha Rai(Abby_akku)
PHP
Javascript
输出:
Rabbits = 50
Pigeons = 50