给定字符串str ,任务是使用正则表达式检查给定的字符串是否为有效的IFSC(印度金融系统)代码。
有效的IFSC(印度金融系统)代码必须满足以下条件:
- 它应该是11个字符长。
- 前四个字符应为大写字母。
- 第五个字符应为0。
- 最后六个字符通常是数字,但也可以是字母。
例子:
Input: str = “SBIN0125620”;
Output: true
Explanation:
The given string satisfies all the above mentioned conditions. Therefore it is a valid IFSC (Indian Financial System) Code.
Input: str = “SBIN0125”;
Output: false
Explanation:
The given string has 8 characters. Therefore it is not a valid IFSC (Indian Financial System) Code.
Input: str = “1234SBIN012”;
Output: false
Explanation:
The given string doesn’t starts with alphabets. Therefore it is not a valid IFSC (Indian Financial System) Code.
方法:想法是使用正则表达式解决此问题。可以按照以下步骤计算答案。
- 获取字符串。
- 创建一个正则表达式来检查有效的IFSC(印度金融系统)代码,如下所述:
regex = "^[A-Z]{4}0[A-Z0-9]{6}$";
- 在哪里:
- ^表示字符串的开头。
- [AZ] {4}表示前四个字符应为大写字母。
- 0表示第五个字符应为0。
- [A-Z0-9] {6}表示接下来的六个字符,通常为数字,但也可以为字母。
- $表示字符串的结尾。
下面是上述方法的实现:
C++
// C++ program to validate the
// IFSC (Indian Financial System) Code using Regular Expression
#include
#include
using namespace std;
// Function to validate the IFSC (Indian Financial System) Code.
bool isValidIFSCode(string str)
{
// Regex to check valid IFSC (Indian Financial System) Code.
const regex pattern("^[A-Z]{4}0[A-Z0-9]{6}$");
// If the IFSC (Indian Financial System) Code
// is empty return false
if (str.empty())
{
return false;
}
// Return true if the IFSC (Indian Financial System) Code
// matched the ReGex
if(regex_match(str, pattern))
{
return true;
}
else
{
return false;
}
}
// Driver Code
int main()
{
// Test Case 1:
string str1 = "SBIN0125620";
cout << isValidIFSCode(str1) << endl;
// Test Case 2:
string str2 = "SBIN0125";
cout << isValidIFSCode(str2) << endl;
// Test Case 3:
string str3 = "1234SBIN012";
cout << isValidIFSCode(str3) << endl;
// Test Case 4:
string str4 = "SBIN7125620";
cout << isValidIFSCode(str4) << endl;
return 0;
}
// This code is contributed by yuvraj_chandra
Java
// Java program to validate
// IFSC (Indian Financial System) Code
// using regular expression.
import java.util.regex.*;
class GFG {
// Function to validate
// IFSC (Indian Financial System) Code
// using regular expression.
public static boolean
isValidIFSCode(String str)
{
// Regex to check valid IFSC Code.
String regex
= "^[A-Z]{4}0[A-Z0-9]{6}$";
// Compile the ReGex
Pattern p
= Pattern.compile(regex);
// If the string is empty
// return false
if (str == null) {
return false;
}
// Pattern class contains matcher()
// method to find matching between
// the given string and
// the regular expression.
Matcher m = p.matcher(str);
// Return if the string
// matched the ReGex
return m.matches();
}
// Driver Code.
public static void main(String args[])
{
// Test Case 1:
String str1 = "SBIN0125620";
System.out.println(isValidIFSCode(str1));
// Test Case 2:
String str2 = "SBIN0125";
System.out.println(isValidIFSCode(str2));
// Test Case 3:
String str3 = "1234SBIN012";
System.out.println(isValidIFSCode(str3));
// Test Case 4:
String str4 = "SBIN7125620";
System.out.println(isValidIFSCode(str4));
}
}
Python3
# Python3 program to validate
# IFSC (Indian Financial System) Code
# using regular expression
import re
# Function to validate
# IFSC (Indian Financial System) Code
# using regular expression.
def isValidIFSCode(str):
# Regex to check valid IFSC Code.
regex = "^[A-Z]{4}0[A-Z0-9]{6}$"
# Compile the ReGex
p = re.compile(regex)
# If the string is empty
# return false
if (str == None):
return False
# Return if the string
# matched the ReGex
if(re.search(p, str)):
return True
else:
return False
# Driver code
# Test Case 1:
str1 = "SBIN0125620"
print(isValidIFSCode(str1))
# Test Case 2:
str2 = "SBIN0125"
print(isValidIFSCode(str2))
# Test Case 3:
str3 = "1234SBIN012"
print(isValidIFSCode(str3))
# Test Case 4:
str4 = "SBIN7125620"
print(isValidIFSCode(str4))
# This code is contributed by avanitrachhadiya2155
输出:
true
false
false
false