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📜  按排序顺序打印字符串数组,而无需将一个字符串复制到另一个字符串

📅  最后修改于: 2021-05-07 10:18:06             🧑  作者: Mango

给定一个由n个字符串的数组。任务是按排序顺序打印字符串。该方法应确保在排序过程中不应将任何字符串复制到另一个字符串。


例子:

Input : {"geeks", "for", "geeks", "quiz")
Output : for geeks geeks quiz

Input : {"ball", "pen", "apple", "kite"}
Output : apple ball kite pen

方法:它具有以下步骤:

  1. 维护另一个数组indexed_arr ,该数组存储/维护每个字符串的索引。
  2. 我们可以将任何排序技术应用于此indexed_arr

插图:

--> str[] = {"world", "hello"}
--> corresponding index array will be
    indexed_arr = {0, 1}
--> Now, how the strings are compared and 
    accordingly values in indexed_arr are changed.
--> Comparison process:
    if (str[index[0]].compare(str[index[1]] > 0
        temp = index[0]
        index[0] = index[1]
        index[1] = temp

// after sorting values of
// indexed_arr = {1, 0}
--> for i=0 to 1
        print str[index[i]]

This is how the strings are compared and their 
corresponding indexes in the indexed_arr
are being manipulated/swapped so that after the sorting process
is completed, the order of indexes in the indexed_arr
gives us the sorted order of the strings.

C++
// C++ implementation to print array of strings in sorted
// order without copying one string into another
#include 
  
using namespace std;
  
// function to print strings in sorted order
void printInSortedOrder(string arr[], int n)
{
    int index[n];
    int i, j, min;
      
    // Initially the index of the strings
    // are assigned to the 'index[]' 
    for (i=0; i 0)
                min = j;
        }
          
        // index of the smallest string is placed
        // at the ith index of 'index[]'
        if (min != i)
        {
            int temp = index[min];
            index[min] = index[i];
            index[i] = temp;
        }
    }
      
    // printing strings in sorted order
    for (i=0; i


Java
//Java implementation to print array of strings in sorted
// order without copying one string into another
  
class GFG {
  
    // function to print strings in sorted order
    static void printInSortedOrder(String arr[], int n) {
        int index[] = new int[n];
        int i, j, min;
  
        // Initially the index of the strings
        // are assigned to the 'index[]' 
        for (i = 0; i < n; i++) {
            index[i] = i;
        }
  
        // selection sort technique is applied    
        for (i = 0; i < n - 1; i++) {
            min = i;
            for (j = i + 1; j < n; j++) {
                // with the help of 'index[]'
                // strings are being compared
                if (arr[index[min]].compareTo(arr[index[j]]) > 0) {
                    min = j;
                }
            }
  
            // index of the smallest string is placed
            // at the ith index of 'index[]'
            if (min != i) {
                int temp = index[min];
                index[min] = index[i];
                index[i] = temp;
            }
        }
  
        // printing strings in sorted order
        for (i = 0; i < n; i++) {
            System.out.print(arr[index[i]] + " ");
        }
    }
  
    // Driver program to test above
    static public void main(String[] args) {
        String arr[] = {"geeks", "quiz", "geeks", "for"};
        int n = 4;
        printInSortedOrder(arr, n);
    }
}
  
// This code is contributed by 29AjayKumar


Python 3
# Python 3 implementation to print array 
# of strings in sorted order without 
# copying one string into another
  
# function to print strings in sorted order
def printInSortedOrder(arr, n):
    index = [0] * n
      
    # Initially the index of the strings
    # are assigned to the 'index[]' 
    for i in range(n):
        index[i] = i
      
    # selection sort technique is applied 
    for i in range(n - 1):
        min = i
        for j in range(i + 1, n):
              
            # with the help of 'index[]'
            # strings are being compared
            if (arr[index[min]] > arr[index[j]]):
                min = j
          
        # index of the smallest string is placed
        # at the ith index of 'index[]'
        if (min != i):
            index[min], index[i] = index[i], index[min]
      
    # printing strings in sorted order
    for i in range(n):
        print(arr[index[i]], end = " ")
  
# Driver Code
if __name__ == "__main__":
      
    arr = ["geeks", "quiz", "geeks", "for"]
    n = 4
    printInSortedOrder(arr, n)
  
# This code is contributed by ita_c


C#
//C# implementation to print an array of strings in sorted
// order without copying one string into another
 using System;
public class GFG {
   
    // function to print strings in sorted order
    static void printInSortedOrder(String []arr, int n) {
        int []index = new int[n];
        int i, j, min;
   
        // Initially the index of the strings
        // are assigned to the 'index[]' 
        for (i = 0; i < n; i++) {
            index[i] = i;
        }
   
        // selection sort technique is applied    
        for (i = 0; i < n - 1; i++) {
            min = i;
            for (j = i + 1; j < n; j++) {
                // with the help of 'index[]'
                // strings are being compared
                if (arr[index[min]].CompareTo(arr[index[j]]) > 0) {
                    min = j;
                }
            }
   
            // index of the smallest string is placed
            // at the ith index of 'index[]'
            if (min != i) {
                int temp = index[min];
                index[min] = index[i];
                index[i] = temp;
            }
        }
   
        // printing strings in sorted order
        for (i = 0; i < n; i++) {
            Console.Write(arr[index[i]] + " ");
        }
    }
   
    // Driver program to test above
    static public void Main() {
        String []arr = {"geeks", "quiz", "geeks", "for"};
        int n = 4;
        printInSortedOrder(arr, n);
    }
}
   
// This code is contributed by 29AjayKumar


输出:

for geeks geeks quiz

时间复杂度: O(n 2 )

当我们必须最小化磁盘写入的次数(例如在结构数组的情况下)时,可以使用这种方法。比较结构值,但不交换它们的值,而是将它们的索引保存在另一个数组中,对该数组进行操作以使索引保持顺序,该顺序代表结构的排序数组。

练习:在其他排序技术(例如合并排序,插入排序等)的帮助下应用此方法。