给定大小为N的字符串str ,其中仅包含两种字符“ I”或“ D” 。任务是生成数组arr [0,1,,。 。 N]的大小N + 1满足以下条件:
- 如果str [i] ==“ I”,则arr [i]
- 如果str [i] ==“ D”,则arr [i]> arr [i + 1]
例子:
Input: str = “IDID”
Output: 0 4 1 3 2
Explaination:
str[0] == “I” therfore arr[0] < arr[1]
str[1] == “D” therfore arr[1] > arr[2]
str[2] == “I” therfore arr[2] < arr[3]
str[3] == “D” therfore arr[3] > arr[4]
Input: str = “III”
Output: 0 1 2 3
方法:
- 将变量START初始化为0 ,将END初始化为N。
- 遍历整个数组。
- 如果str [i] == “ I”,则在arr [i]处分配START并递增START 。
- 如果str [i] == “ D”,则在arr [i]处分配END并减小END 。
- 现在未分配数组的最后一个元素,因此在A [N]处分配START 。
下面是该方法的实现。
C++
// C++ program to Generate an increasing
// and decreasing array
#include
using namespace std;
// Function that returns generated array
int* DiStirngMatch(string Str)
{
int N = Str.length();
// Dynamically allocate array
int* arr = new int[N];
// START=0, END=N
int START = 0, END = N;
// iterate over array
for (int i = 0; i < N; i++) {
// if Str[i]=='I' assign arr[i]
// as START and increment START
if (Str[i] == 'I')
arr[i] = START++;
// if str[i]=='D' assign arr[i]
// as END and decrement END
if (Str[i] == 'D')
arr[i] = END--;
}
// assign A[N] as START
arr[N] = START;
// return starting
// address of array A
return arr;
}
// Driver Program
int main()
{
string Str = "IDID";
int N = Str.length();
int* ptr = DiStirngMatch(Str);
for (int i = 0; i <= N; i++)
cout << ptr[i] << " ";
return 0;
}
Java
// Java program to generate an increasing
// and decreasing array
class GFG{
// Function that returns generated array
static int []DiStirngMatch(String Str)
{
int N = Str.length();
// Dynamically allocate array
int []arr = new int[N + 1];
// START=0, END=N
int START = 0, END = N;
// Iterate over array
for(int i = 0; i < N; i++)
{
// if Str[i]=='I' assign arr[i]
// as START and increment START
if (Str.charAt(i) == 'I')
arr[i] = START++;
// if str[i]=='D' assign arr[i]
// as END and decrement END
if (Str.charAt(i) == 'D')
arr[i] = END--;
}
// Assign A[N] as START
arr[N] = START;
// Return starting
// address of array A
return arr;
}
// Driver code
public static void main(String[] args)
{
String Str = "IDID";
int N = Str.length();
int[] ptr = DiStirngMatch(Str);
for(int i = 0; i <= N; i++)
System.out.print(ptr[i] + " ");
}
}
// This code is contributed by amal kumar choubey
Python3
# Python3 program to generate an
# increasing and decreasing array
# Function that returns generated array
def DiStirngMatch(Str):
N = len(Str)
# Dynamically allocate array
arr = (N + 1) * [0]
# START, END= 0 ,N
START, END = 0, N
# Iterate over array
for i in range (N):
# If Str[i]=='I' assign arr[i]
# as START and increment START
if (Str[i] == 'I'):
arr[i] = START
START += 1
# If str[i]=='D' assign arr[i]
# as END and decrement END
if (Str[i] == 'D'):
arr[i] = END
END -= 1
# Assign A[N] as START
arr[N] = START
# Return starting
# address of array A
return arr
# Driver code
if __name__ == "__main__":
Str = "IDID"
N = len(Str)
ptr = DiStirngMatch(Str)
for i in range (N + 1):
print(ptr[i], end = " ")
# This code is contributed by chitranayal
C#
// C# program to generate an increasing
// and decreasing array
using System;
class GFG{
// Function that returns generated array
static int []DiStirngMatch(String Str)
{
int N = Str.Length;
// Dynamically allocate array
int []arr = new int[N + 1];
// START=0, END=N
int START = 0, END = N;
// Iterate over array
for(int i = 0; i < N; i++)
{
// if Str[i]=='I' assign arr[i]
// as START and increment START
if (Str[i] == 'I')
arr[i] = START++;
// if str[i]=='D' assign arr[i]
// as END and decrement END
if (Str[i] == 'D')
arr[i] = END--;
}
// Assign A[N] as START
arr[N] = START;
// Return starting
// address of array A
return arr;
}
// Driver code
public static void Main(String[] args)
{
String Str = "IDID";
int N = Str.Length;
int[] ptr = DiStirngMatch(Str);
for(int i = 0; i <= N; i++)
Console.Write(ptr[i] + " ");
}
}
// This code is contributed by amal kumar choubey
输出:
0 4 1 3 2
时间复杂度: O(N)
辅助空间: O(N)