C语言中的随机密码生成器

在本文中，我们将讨论如何生成由任意字符组成的给定长度的随机密码。

方法：

• 下面给出的程序涉及一些基本概念，例如变量，数据类型，数组，循环等。
• 请按照以下步骤解决此问题：
  • 取密码的长度，并声明一个该长度的字符数组以存储该密码。
  • 声明所有大写字母，小写字母，数字和特殊字符的字符数组。
  • 现在，根据下面的程序，将执行相应的if-else并生成一个随机密码。

下面是上述方法的程序：

C

// C program for the above approach
#include 
#include 
#include 
#include 
  
// Function to randomly generates password
// of length N
void randomPasswordGeneration(int N)
{
    // Initialize counter
    int i = 0;
  
    int randomizer = 0;
  
    // Seed the random-number generator
    // with current time so that the
    // numbers will be different every time
    srand((unsigned int)(time(NULL)));
  
    // Array of numbers
    char numbers[] = "0123456789";
  
    // Array of small alphabets
    char letter[] = "abcdefghijklmnoqprstuvwyzx";
  
    // Array of capital alphabets
    char LETTER[] = "ABCDEFGHIJKLMNOQPRSTUYWVZX";
  
    // Array of all the special symbols
    char symbols[] = "!@#$^&*?";
  
    // Stores the random password
    char password[N];
  
    // To select the randomizer
    // inside the loop
    randomizer = rand() % 4;
  
    // Iterate over the range [0, N]
    for (i = 0; i < N; i++) {
  
        if (randomizer == 1) {
            password[i] = numbers[rand() % 10];
            randomizer = rand() % 4;
            printf("%c", password[i]);
        }
        else if (randomizer == 2) {
            password[i] = symbols[rand() % 8];
            randomizer = rand() % 4;
            printf("%c", password[i]);
        }
        else if (randomizer == 3) {
            password[i] = LETTER[rand() % 26];
            randomizer = rand() % 4;
            printf("%c", password[i]);
        }
        else {
            password[i] = letter[rand() % 26];
            randomizer = rand() % 4;
            printf("%c", password[i]);
        }
    }
}
  
// Driver Code
int main()
{
    // Length of the password to
    // be generated
    int N = 10;
  
    // Function Call
    randomPasswordGeneration(N);
  
    return 0;
}

输出：

51WAZMT?Z$

时间复杂度： O(N)
辅助空间： O(26)