给定正整数n,请检查在n的二进制表示形式中是否仅设置了第一位和最后一位。打印“是”或“否”。
例子:
Input: 9
Output: Yes
(9)10 = (1001)2, only the first and
last bits are set.
Input: 15
Output: No
(15)10 = (1111)2, except first and last
there are other bits also which are set.
我们已经在这里讨论了一个解决方案。
在这篇文章中,讨论了一个更简单的解决方案。
C++
// C++ to check whether the number has only
// first and last bits set
#include
using namespace std;
// function to check whether the number has only
// first and last bits set
bool onlyFirstAndLastAreSet(unsigned int n)
{
if (n == 1)
return true;
if (n == 2)
return false;
return (((n - 1) & (n - 2)) == 0);
}
// Driver program to test above
int main()
{
unsigned int n = 9;
if (onlyFirstAndLastAreSet(n))
cout << "Yes";
else
cout << "No";
return 0;
}
Java
// Java to check whether
// the number has only
// first and last bits set
class GFG
{
// function to check whether
// the number has only
// first and last bits set
static boolean onlyFirstAndLastAreSet(int n)
{
if (n == 1)
return true;
if (n == 2)
return false;
return (((n - 1) &
(n - 2)) == 0);
}
// Driver Code
public static void main(String[] args)
{
int n = 9;
if (onlyFirstAndLastAreSet(n))
System.out.println("Yes");
else
System.out.println("No");
}
}
// This code is contributed
// by Smitha
Python3
# Python 3 to check whether
# the number has only
# first and last bits set
# function to check whether
# the number has only
# first and last bits set
def onlyFirstAndLastAreSet(n):
if (n == 1):
return True
if (n == 2):
return False
return (((n - 1) &
(n - 2)) == 0)
# Driver Code
n = 9
if (onlyFirstAndLastAreSet(n)):
print("Yes")
else:
print("No")
# This code is contributed
# by Smitha
C#
// C# to check whether
// the number has only
// first and last bits set
using System;
class GFG
{
// function to check whether
// the number has only
// first and last bits set
static bool onlyFirstAndLastAreSet(int n)
{
if (n == 1)
return true;
if (n == 2)
return false;
return (((n - 1) &
(n - 2)) == 0);
}
// Driver Code
public static void Main()
{
int n = 9;
if (onlyFirstAndLastAreSet(n))
Console.Write("Yes");
else
Console.Write("No");
}
}
// This code is contributed
// by Smitha
PHP
Javascript
输出:
Yes