C语言中的ispunct()函数

ispunct()函数检查字符是否为标点字符。
此函数定义的术语“标点符号”包括所有可打印的字符，这些字符既不是字母数字也不是空格。例如“ @”，“ $”等。
此函数在ctype.h头文件中定义。

int ispunct(int ch);
ch: character to be checked.
Return Value  : function return nonzero
 if character is a punctuation character;
 otherwise zero is returned. 

// Program to check punctuation
#include 
#include 
int main()
{
    // The puncuations in str are '!' and ','
    char str[] = "welcome! to GeeksForGeeks, ";
  
    int i = 0, count = 0;
    while (str[i]) {
        if (ispunct(str[i]))
            count++;
        i++;
    }
    printf("Sentence contains %d punctuation"
           " characters.\n", count);
    return 0;
}

输出：

Sentence contains 2 punctuation characters.

// C program to print all Punctuations
#include 
#include 
int main()
{
    int i;
    printf("All punctuation characters in C"
            " programming are: \n");
    for (i = 0; i <= 255; ++i)
        if (ispunct(i) != 0)
            printf("%c ", i);
    return 0;
}

输出：

All punctuation characters in C programming are: 
! " # $ % & ' ( ) * +, - . / : ;  ? @ [ \ ] ^ _ ` { | } ~

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