给定两个浮点数,找到余数。
例子:
Input: a = 36.5, b = 5.0
Output: 1.5
Input: a = 9.7, b = 2.3
Output: 0.5
一个简单的解决方案是进行重复减法。
C++
// C++ program to find modulo of floating
// point numbers.
#include
using namespace std;
double findMod(double a, double b)
{
double mod;
// Handling negative values
if (a < 0)
mod = -a;
else
mod = a;
if (b < 0)
b = -b;
// Finding mod by repeated subtraction
while (mod >= b)
mod = mod - b;
// Sign of result typically depends
// on sign of a.
if (a < 0)
return -mod;
return mod;
}
// Driver Function
int main()
{
double a = 9.7, b = 2.3;
cout << findMod(a, b);
return 0;
}
Java
// Java program to find modulo of floating
// point numbers
class GFG
{
static double findMod(double a, double b)
{
// Handling negative values
if (a < 0)
a = -a;
if (b < 0)
b = -b;
// Finding mod by repeated subtraction
double mod = a;
while (mod >= b)
mod = mod - b;
// Sign of result typically depends
// on sign of a.
if (a < 0)
return -mod;
return mod;
}
// Driver code
public static void main (String[] args)
{
double a = 9.7, b = 2.3;
System.out.print(findMod(a, b));
}
}
// This code is contributed by Anant Agarwal.
Python3
# Python3 program to find modulo
# of floating point numbers.
def findMod(a, b):
# Handling negative values
if (a < 0):
a = -a
if (b < 0):
b = -b
# Finding mod by repeated subtraction
mod = a
while (mod >= b):
mod = mod - b
# Sign of result typically
# depends on sign of a.
if (a < 0):
return -mod
return mod
# Driver code
a = 9.7; b = 2.3
print(findMod(a, b))
# This code is contributed by Anant Agarwal.
C#
// C# program to find modulo of floating
// point numbers
using System;
class GFG {
static double findMod(double a, double b)
{
// Handling negative values
if (a < 0)
a = -a;
if (b < 0)
b = -b;
// Finding mod by repeated subtraction
double mod = a;
while (mod >= b)
mod = mod - b;
// Sign of result typically depends
// on sign of a.
if (a < 0)
return -mod;
return mod;
}
// Driver code
public static void Main ()
{
double a = 9.7, b = 2.3;
Console.WriteLine(findMod(a, b));
}
}
// This code is contributed by vt_m.
PHP
= $b)
$mod = $mod - $b;
// Sign of result typically
// depends on sign of a.
if ($a < 0)
return -$mod;
return $mod;
}
// Driver Code
$a = 9.7; $b = 2.3;
echo findMod($a, $b);
// This code is contributed by anuj_65.
?>
Javascript
C++
// CPP program to find modulo of floating
// point numbers using library function.
#include
using namespace std;
// Driver Function
int main()
{
double a = 9.7, b = 2.3;
cout << fmod(a, b);
return 0;
}
Python3
# Python3 program to find modulo of floating
# point numbers using library function.
from math import fmod
# Driver code
if __name__ == '__main__':
a = 9.7
b = 2.3
print(fmod(a, b))
# This code is contributed by mohit kumar 29
PHP
Javascript
Java
// JAVA program to find modulo of floating
// point numbers using library function.
import java.util.*;
class GFG{
// Driver Function
public static void main(String[] args)
{
double a = 9.7, b = 2.3;
System.out.print((a % b));
}
}
// This code contributed by umadevi9616
输出 :
0.5
我们可以使用内置的fmod函数来找到两个浮点数的模数。
C++
// CPP program to find modulo of floating
// point numbers using library function.
#include
using namespace std;
// Driver Function
int main()
{
double a = 9.7, b = 2.3;
cout << fmod(a, b);
return 0;
}
Python3
# Python3 program to find modulo of floating
# point numbers using library function.
from math import fmod
# Driver code
if __name__ == '__main__':
a = 9.7
b = 2.3
print(fmod(a, b))
# This code is contributed by mohit kumar 29
的PHP
Java脚本
Java
// JAVA program to find modulo of floating
// point numbers using library function.
import java.util.*;
class GFG{
// Driver Function
public static void main(String[] args)
{
double a = 9.7, b = 2.3;
System.out.print((a % b));
}
}
// This code contributed by umadevi9616
输出:
0.5
要从最佳影片策划和实践问题去学习,检查了C++基础课程为基础,以先进的C++和C++ STL课程基础加上STL。要完成从学习语言到DS Algo等的更多准备工作,请参阅“完整面试准备课程” 。