问题陈述：编写C程序来构建考试管理系统软件，该软件可以执行以下操作：
- 添加/删除学生的详细信息
- 学生出勤监控
- 设置/编辑考试的资格标准
- 检查符合条件的学生进行考试
- 打印学生的所有记录
方法：想法是为每个操作形成一个单独的函数。所有功能与开关盒统一在一起构成软件。下面是功能说明：
- execute()：此函数将显示软件的可用选项，并将使用Switch语句执行以下功能。
功能性：- 添加学生详细信息
- 显示合格的学生
- 删除学生记录
- 更新资格标准
- 打印学生详细信息
- add()：此函数从用户获取数据并更新学生列表。将学生添加到列表中时，检查学生的卷号的唯一性。要添加的学生的详细信息是：
- 学生的名字
- 卷号
- 费用状态
- 学生出勤记录
- qualitedStudents()：此函数显示考试所需的先前出勤百分比，并从用户那里获取数据并更新考试的资格。它还通过遍历学生记录列表来更新考试资格所需的费用状态，并且对于每个学生检查，出勤率均超出所需的百分比和学生的费用状态。
- print_student()：此函数遍历学生列表并打印学生的详细信息。
- delete()：此函数获取学生成绩编号以删除学生记录并更新学生列表。
下面是说明上述功能的程序：
add()
// Function that adds the student's
// record in Examination Management
// Project
void add(struct student s[50])
{
printf("Enter the total ");
printf("number of working days \n");
scanf("%f", &tdays);
printf("Enter the number"
"of students \n");
scanf("%d", &n);
for (i = 0; i < n; i++) {
printf("Student number %d \n",
(i + 1));
printf("Enter the name of"
" the student \n");
scanf("%s", s[i].name);
printf("Enter the roll number \n");
scanf(" %d", &s[i].rno);
printf("Enter the fees of the"
"student 'P' for paid "
", 'N' for not paid \n");
scanf(" %c", &s[i].fees);
printf("Enter the number of"
"days the student was "
"present \n");
scanf("%f", &s[i].days);
s[i].attend = (s[i].days
/ tdays)
* 100;
printf("student attendence"
" = %f \n",
s[i].attend);
}
execute();
}execute()
// Function to execute the Examination
// Management System
void execute()
{
printf("Enter the serial number "
"to select the option \n");
printf(" 1. To show Eligible"
"candidates \n");
printf(" 2. To delete the "
"student record \n");
printf(" 3. To change the "
"eligibility criteria \n");
printf(" 4. Reset the "
"eligibility criteria \n");
printf(" 5. Print the list "
"of all the student \n");
printf(" Enter 0 to exit \n");
scanf("%d", &option);
// Switch Statement for choosing
// the desired option for user
switch (option) {
case 1:
eligibleStudents(s);
execute();
break;
case 2:
deleteRecord(s);
execute();
break;
case 3:
printf("Old Attendance "
"required = %f",
present);
printf(
"\n Enter the updated "
"attendence required \n");
scanf("%f", &present);
printf("fees status required"
" was %c \n",
money);
printf("Enter the new fees "
"status 'P' for paid 'N' "
"for not paid and "
"'B' for both \n");
scanf("%c", &money);
printf("Eligibility Criteria"
" updated \n");
execute();
break;
case 4:
present = 75.00;
money = 'P';
printf("Eligibility Criteria"
" reset \n");
execute();
break;
case 5:
printStudents(s);
execute();
break;
case 6:
execute();
break;
case 0:
exit(0);
default:
printf("Enter number only"
" from 0 - 4 \n");
execute();
}
}eligibleStudents()
// Function to print the student
// details of the eligible students
void eligibleStudents(struct student s[])
{
printf("________________"
"________________"
"_______________"
"_____________ \n");
printf("Qualified student are = \n");
// Iterate over the list of the
// students records
for (i = 0; i < n; i++) {
// Condition to check the
// eligibility of the student
if (s[i].fees == money || 'B' == money) {
if (s[i].attend >= present) {
printf("Student name = %s \n",
s[i].name);
printf("Student roll no. = %d \n",
s[i].rno);
printf(" Student fees = %c \n",
s[i].fees);
printf(" Student attendence = %f \n",
s[i].attend);
}
}
}
}delete()
// Function to delete any Student Record
void delete (struct student s[])
{
int a = 0;
printf("Enter the roll number of"
"the student to delete it ");
scanf("%d", &a);
// Iterate over the student's
// records to delete the Data
for (i = 0; i <= n; i++) {
// Check the current student
// roll number is same as the
// user input roll number
if (s[i].rno == (a)) {
// Update record at ith index
// with (i + 1)th index
for (j = i; j < n; j++) {
strcpy(s[j].name,
s[j + 1].name);
s[j].rno = s[j + 1].rno;
s[j].fees = s[j + 1].fees;
s[j].days = s[j + 1].days;
s[j].attend = s[j + 1].attend;
}
printf("Student Record deleted");
}
}
}print_student()
// Function to print the students record
void print_student(struct student s[])
{
// Iterate over the students
// students records
for (i = 0; i < n; i++) {
printf("Name of student %s \n",
s[i].name);
printf("Student roll number = %d \n",
s[i].rno);
printf("Student fees status = %c \n",
s[i].fees);
printf("student number of days "
"present = %d \n",
s[i].days);
printf("Student attendence = %f \n",
s[i].attend);
}
}Complete Code
// C program for the Examination
// Management System
#include
#include
#include
int option = 0;
int i = 0;
int n = 0;
int j = 0;
float present = 75.00;
char money = 'P';
float tdays = 1;
// Structure of Student
struct student {
char name[20];
int rno;
char fees;
float days;
float attend;
} s[50];
// Functions
void add(struct student s[]);
void eligibleStudents(struct student s[]);
void execute();
void printStudents(struct student s[]);
void deleteRecord(struct student s[]);
// Function to execute the software
// for the student examination
// registration system
void execute()
{
printf(
" Enter the serial number"
"to select the option \n");
printf(" 1. To show Eligible"
"candidates \n");
printf(" 2. To delete the "
"student record \n");
printf(" 3. To change the "
"eligibility criteria \n");
printf(" 4. Reset the "
"eligibility criteria \n");
printf(" 5. Print the list "
"of all the student \n");
printf(" Enter 0 to exit \n");
scanf("%d", &option);
// Switch Statement for choosing
// the desired option for the user
switch (option) {
case 1:
eligibleStudents(s);
execute();
break;
case 2:
deleteRecord(s);
execute();
break;
case 3:
printf("Old Attendance "
"required = %f",
present);
printf(
"\n Enter the updated "
"attendence required \n");
scanf("%f", &present);
printf("fees status required"
" was %c \n",
money);
printf("Enter the new fees "
"status 'P' for paid 'N' "
"for not paid and "
"'B' for both \n");
scanf("%c", &money);
printf("Eligibility Criteria updated \n");
execute();
break;
case 4:
present = 75.00;
money = 'P';
printf("Eligibility creitria reset \n");
execute();
break;
case 5:
printStudents(s);
execute();
break;
case 6:
execute();
break;
case 0:
exit(0);
default:
printf("Enter number only from 0-4 \n");
execute();
}
}
// Function to print the students record
void printStudents(struct student s[])
{
// Loop to iterate over the students
// students records
for (i = 0; i < n; i++) {
printf("Name of student %s \n",
s[i].name);
printf("Student roll number = %d \n",
s[i].rno);
printf("Student fees status = %c \n",
s[i].fees);
printf("Student number of days "
"present = %f \n",
s[i].days);
printf("Student attendence = %f \n",
s[i].attend);
}
}
// Function to Student Record
void deleteRecord(struct student s[])
{
int a = 0;
printf("Enter the roll number of "
"the student to delete it ");
scanf("%d", &a);
// Loop to iterate over the students
// records to delete the Data
for (i = 0; i <= n; i++) {
// Condition to check the current
// student roll number is same as
// the user input roll number
if (s[i].rno == (a)) {
// Update record at ith index
// with (i + 1)th index
for (j = i; j < n; j++) {
strcpy(s[j].name, s[j + 1].name);
s[j].rno = s[j + 1].rno;
s[j].fees = s[j + 1].fees;
s[j].days = s[j + 1].days;
s[j].attend = s[j + 1].attend;
}
printf("Student Record deleted");
}
}
}
// Function to print the student
// details of the eligible students
void eligibleStudents(struct student s[])
{
printf("________________"
"________________"
"_______________"
"_____________ \n");
printf("Qualified student are = \n");
// Iterate over the list
// of the students records
for (i = 0; i < n; i++) {
// Check for the eligibility
// of the student
if (s[i].fees == money || 'B' == money) {
if (s[i].attend >= present) {
printf("Student name = %s \n",
s[i].name);
printf("Student roll no. = %d \n",
s[i].rno);
printf(" Student fees = %c \n",
s[i].fees);
printf(" Student attendence = %f \n",
s[i].attend);
}
}
}
}
// Function to add the students record
void add(struct student s[50])
{
printf("Enter the total ");
printf("number of working days \n");
scanf("%f", &tdays);
printf("Enter the number");
printf("of students \n");
scanf("%d", &n);
for (i = 0; i < n; i++) {
printf("Student number %d \n",
(i + 1));
printf("Enter the name of"
" the student \n");
scanf("%s", s[i].name);
printf("Enter the roll number \n");
scanf(" %d", &s[i].rno);
printf("Enter the fees of the"
"student 'P' for paid "
", 'N' for not paid \n");
scanf(" %c", &s[i].fees);
printf("Enter the number of"
"days the student was "
"present \n");
scanf("%f", &s[i].days);
s[i].attend = (s[i].days
/ tdays)
* 100;
printf("student attendence = %f \n",
s[i].attend);
}
execute();
}
// Driver Code
int main()
{
printf("Welcome to Student "
"database registration \n");
printf("Enter 0 to exit \n");
printf("Enter 1 to add student"
" record \n");
scanf("%d", &option);
// Switch Statements
switch (option) {
case 0:
exit(0);
case 1:
add(s);
break;
default:
printf("Only enter 0 or 1");
execute();
}
return 0;
} 输出：
以下是上述功能的输出：
- 要添加学生的详细信息，请执行以下操作：
- 对于符合条件的学生：
- 资格标准：
- 打印学生的详细信息：
- 删除学生记录：
想要从精选的最佳视频中学习和练习问题，请查看《基础知识到高级C的C基础课程》。