Array.Exists(T [],Predicate
句法:
public static bool Exists (T[] array, Predicate match);
参数:
array: It is a one-dimensional, zero-based Array to search.
match: It is a Predicate that defines the conditions of the elements to search for. Where T is a type of the elements present in the array.
返回值:该方法的返回类型为System.Boolean 。如果数组包含一个或多个与指定谓词定义的条件匹配的元素,则返回true。否则,返回false 。
异常:如果array的值为null,或者match的值为null,则此方法将提供ArgumentNullException 。
下面给出了一些示例,以更好地理解实现:
范例1:
// C# program to illustrate the
// Array.Exists(T[], Predicate) Method
using System;
class GFG {
// Main method
static public void Main()
{
// Create and initialize array
string[] language = {"Ruby", "C", "C++", "Java",
"Perl", "C#", "Python", "PHP"};
// Display language array
Console.WriteLine("Display the array:");
foreach(string i in language)
{
Console.WriteLine(i);
}
// Display and check the given elements
// present in the array or not
// Using Exists() method
Console.WriteLine("Is Ruby part of language: {0}",
Array.Exists(language, element => element == "Ruby"));
Console.WriteLine("Is VB part of language: {0}",
Array.Exists(language, element => element == "VB"));
}
}
输出:
Display the array:
Ruby
C
C++
Java
Perl
C#
Python
PHP
Is Ruby part of language: True
Is VB part of language: False
范例2:
// C# program to illustrate the
// Array.Exists(T[], Predicate) Method
using System;
public class GFG {
// Main method
static public void Main()
{
// Create and initialize array
string[] ds = {"Array", "Queue", "LinkedList",
"Stack", "Graph" };
// Display ds array
Console.WriteLine("Given Array: ");
foreach(string i in ds)
{
Console.WriteLine(i);
}
// Display and check the given elements with the
// specified letter is present in the array or not
// Using Exists() method
Console.WriteLine("Is element start with L letter is present in array: {0}",
Array.Exists(ds, element => element.StartsWith("L")));
Console.WriteLine("Is element start with O letter is present in array: {0}",
Array.Exists(ds, element => element.StartsWith("O")));
}
}
输出:
Given Array:
Array
Queue
LinkedList
Stack
Graph
Is element start with L letter is present in array: True
Is element start with O letter is present in array: False
注意:此方法是O(n)运算,其中n是数组的长度。
参考: https://docs.microsoft.com/zh-cn/dotnet/api/system.array.exists?view=netcore-2.1#definition