C＃中的TimeSpan.FromMinutes()方法

此方法用于获取表示指定分钟数的TimeSpan，其中规格精确到最接近的毫秒。

Syntax: public static TimeSpan FromMinutes (double value);

Parameter:
value: This parameter specifies the number of minutes, accurate to the nearest millisecond.

Return Value: It returns a new TimeSpan object that represents the value.

例外情况：

• OverflowException：如果给定的double值小于最小可能值或大于最大可能值，或者该值是PositiveInfinity或NegativeInfinity。
• ArgumentException：如果值为NaN。

下面的程序说明了TimeSpan.FromMinutes(Double)Method的用法：

范例1：

// C# program to demonstrate the
// TimeSpan.FromMinutes(Double) Method
using System;
  
class GFG {
  
    // Main Method
    public static void Main()
    {
        try {
  
            TimeSpan interval = TimeSpan.FromMinutes(8.12345);
            Console.WriteLine("The Timespan is : {0}",
                                            interval);
        }
  
        catch (OverflowException e) 
        {
            Console.Write("Exception Thrown: ");
            Console.Write("{0}", e.GetType(), e.Message);
        }
    }
}

输出：

The Timespan is : 00:08:07.4070000

示例2：对于溢出异常

// C# program to demonstrate the
// TimeSpan.FromMinutes(Double) Method
using System;
  
class GFG {
  
    // Main Method
    public static void Main()
    {
        try {
  
            TimeSpan interval = 
               TimeSpan.FromMinutes(Double.PositiveInfinity);
  
            Console.WriteLine("The Timespan is : {0}",
                                            interval);
        }
  
        catch (OverflowException e) 
        {
            Console.Write("Exception Thrown: ");
            Console.Write("{0}", e.GetType(), e.Message);
        }
    }
}

输出：

Exception Thrown: System.OverflowException

参考：

• https://docs.microsoft.com/zh-cn/dotnet/api/system.timespan.fromminutes?view=netframework-4.7.2