给定两个数组,请在C++中使用STL将这两个数组连接在一起。
例子:
Input:
arr1[] = {1, 45, 54, 71, 76, 12},
arr2[] = {1, 7, 5, 4, 6, 12}
Output: {1, 4, 5, 6, 7, 12, 45, 54, 71, 76}
Input:
arr1[] = {1, 7, 5, 4, 6, 12},
arr2[] = {10, 12, 11}
Output: {1, 4, 5, 6, 7, 10, 11, 12}
方法:可以借助STL中提供的set_union()函数来完成连接。
句法:
set_union (InputIterator1 first1, InputIterator1 last1,
InputIterator2 first2, InputIterator2 last2,
OutputIterator result);
下面是上述方法的实现:
// C++ program to join two Arrays
// using set_union() in STL
#include
using namespace std;
int main()
{
// Get the array
int arr1[] = { 1, 45, 54, 71, 76, 12 };
int arr2[] = { 1, 7, 5, 4, 6, 12 };
// Compute the sizes
int n1 = sizeof(arr1) / sizeof(arr1[0]);
int n2 = sizeof(arr2) / sizeof(arr2[0]);
// Sort the arrays
sort(arr1, arr1 + n1);
sort(arr2, arr2 + n2);
// Print the array
cout << "First Array: ";
for (int i = 0; i < n1; i++)
cout << arr1[i] << " ";
cout << endl;
cout << "Second Array: ";
for (int i = 0; i < n2; i++)
cout << arr2[i] << " ";
cout << endl;
// Initialise a vector
// to store the merged values
// and an iterator
// to traverse this vector
vector v(n1 + n2);
vector::iterator it, st;
it = set_union(arr1, arr1 + n1,
arr2, arr2 + n2,
v.begin());
// Print the merged array
cout << "\nAfter joining:\n";
for (st = v.begin(); st != it; ++st)
cout << *st << ", ";
cout << '\n';
return 0;
}
输出:
First Array: 1 12 45 54 71 76
Second Array: 1 4 5 6 7 12
After joining:
1, 4, 5, 6, 7, 12, 45, 54, 71, 76,
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