从字符串中拆分数字，字母和特殊符号

在给定字符串str的情况下，将字符串分为三部分，一个包含数字部分，一个包含字母部分，另一个包含特殊字符。

例子：

Input : geeks01for02geeks03!!!
Output :geeksforgeeks
        010203
        !!!
Here str = "Geeks01for02Geeks03!!!", we scan every character and 
append in res1, res2 and res3 string accordingly.

Input : **Docoding123456789everyday##
Output :Docodingeveryday
        123456789
        **##

脚步 ：

1. 计算字符串的长度。
2. 逐一扫描字符串的每个字符(ch)
   • 如果(ch是数字)，则将其附加到res1字符串。
   • 否则，如果(ch是字母)附加在字符串res2中。
   • 否则附加在字符串res3中。
3. 打印所有字符串，我们将有一个字符串包含数字部分，其他非数字部分，最后一个包含特殊字符。

C++

// CPP program to split an alphanumeric
// string using STL
#include
using namespace std;
 
void splitString(string str)
{
    string alpha, num, special;
    for (int i=0; i= 'A' && str[i] <= 'Z') ||
                (str[i] >= 'a' && str[i] <= 'z'))
            alpha.push_back(str[i]);
        else
            special.push_back(str[i]);
    }
 
    cout << alpha << endl;
    cout << num << endl;
    cout << special << endl;
}
 
// Driver code
int main()
{
    string str = "geeks01$$for02geeks03!@!!";
    splitString(str);
    return 0;
}

Java

// CPP program to split an alphanumeric
// string using stringbuffer
 
class Test
{
    static void splitString(String str)
    {
        StringBuffer alpha = new StringBuffer(),
        num = new StringBuffer(), special = new StringBuffer();
         
        for (int i=0; i

---

Python3

# Python 3 program to split an alphanumeric
# string using STL
def splitString(str):
 
    alpha = ""
    num = ""
    special = ""
    for i in range(len(str)):
        if (str[i].isdigit()):
            num = num+ str[i]
        elif((str[i] >= 'A' and str[i] <= 'Z') or
             (str[i] >= 'a' and str[i] <= 'z')):
            alpha += str[i]
        else:
            special += str[i]
 
    print(alpha)
    print(num )
    print(special)
 
# Driver code
if __name__ == "__main__":
     
    str = "geeks01$$for02geeks03!@!!"
    splitString(str)
 
# This code is contributed by ita_c

C#

// C# program to split an alphanumeric
// string using stringbuffer
using System;
using System.Text;
 
class GFG  {
     
    // Function ot split string
    static void splitString(string str)
    {
        StringBuilder alpha =
                 new StringBuilder();
        StringBuilder num =
                 new StringBuilder();
        StringBuilder special =
                 new StringBuilder();
     
        for (int i = 0; i < str.Length; i++)
        {
            if (Char.IsDigit(str[i]))
                num.Append(str[i]);
            else if((str[i] >= 'A' &&
                     str[i] <= 'Z') ||
                     (str[i] >= 'a' &&
                      str[i] <= 'z'))
                alpha.Append(str[i]);
            else
                special.Append(str[i]);
        }
     
        Console.WriteLine(alpha);
        Console.WriteLine(num);
        Console.WriteLine(special);
    }
     
    // Driver code
    public static void Main()
    {
        string str = "geeks01$$for02geeks03!@!!";
        splitString(str);
    }
}
 
// This code is contributed by Sam007

Javascript

// Javascript program to split an alphanumeric
// string using stringbuffer   
     
    function splitString(str)
    {
        let alpha = "";
        let num = "";
        let special = "";
        for (let i=0; i<str.length; i++)
        {
            if (!isNaN(String(str[i]) * 1))
                num+=str[i];
            else if((str[i] >= 'A' && str[i] <= 'Z') ||
             (str[i] >= 'a' && str[i] <= 'z'))
                alpha+=str[i];
            else
                special+=str[i];
        }
        
        document.write(alpha+"<br>");
        document.write(num+"<br>");
        document.write(special+"<br>");
    }
     
    // Driver method
    let str = "geeks01$$for02geeks03!@!!";
    splitString(str);
     
    // This code is contributed by avanitrachhadiya2155

输出：

geeksforgeeks
010203
$$!@!!

上述解决方案的时间复杂度为O(n)，其中n是字符串的长度。

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