检查数组是否可以转换为严格递减的序列

给定数组arr [] ，任务是借助以下操作检查是否可以将给定数组转换为严格递减的序列：

• 在一个操作中将任何元素(如果大于1)减少1

例子：

Input: arr[] = {11, 11, 11, 11} 
Output : Yes 
Explanation: 
The given sequence can be converted into 
arr[] = {11, 10, 9, 8}
Input: arr[] = {1, 1} 
Output: No 
Explanation: 
The given sequence cannot be converted into strictly decreasing sequence 
 

方法：想法是检查数组的每个元素是否大于或等于(N –元素的索引)，因为如果大于或等于(N –元素的索引)，则意味着可以将数组转换为[N，N-1，N-2，…. 1]
下面是上述方法的实现：

C++

// C++ implementation to check that
// array can be converted into a
// strictly decreasing sequence
#include 
using namespace std;
 
// Function to check that array
// can be converted into a
// strictly decreasing sequence
bool check(int* arr, int n)
{
    bool flag = true;
 
    // Loop to check that each element is
    // greater than the (N - index)
    for (int i = 0; i < n; i++) {
 
        // If element is less than (N - index)
        if (arr[i] < n - i) {
            flag = false;
        }
    }
 
    // If array can be converted
    if (flag) {
        return true;
    }
    else {
        return false;
    }
}
 
// Driver Code
int main()
{
    int arr1[] = { 11, 11, 11, 11 };
    int n1 = sizeof(arr1) / sizeof(arr1[0]);
 
    // Function calling
    if (check(arr1, n1)) {
        cout << "Yes" << endl;
    }
    else {
        cout << "No" << endl;
    }
}

Java

// Java implementation to check that
// array can be converted into a
// strictly decreasing sequence
class GFG{
 
// Function to check that array
// can be converted into a
// strictly decreasing sequence
static boolean check(int []arr, int n)
{
    boolean flag = true;
 
    // Loop to check that each element is
    // greater than the (N - index)
    for (int i = 0; i < n; i++)
    {
 
        // If element is less than (N - index)
        if (arr[i] < n - i)
        {
            flag = false;
        }
    }
 
    // If array can be converted
    if (flag)
    {
        return true;
    }
    else
    {
        return false;
    }
}
 
// Driver Code
public static void main(String[] args)
{
    int arr1[] = { 11, 11, 11, 11 };
    int n1 = arr1.length;
 
    // Function calling
    if (check(arr1, n1))
    {
        System.out.print("Yes" + "\n");
    }
    else
    {
        System.out.print("No" + "\n");
    }
}
}
 
// This code is contributed by amal kumar choubey

Python3

# Python3 implementation to check that
# array can be converted into a
# strictly decreasing sequence
 
# Function to check that array
# can be converted into a
# strictly decreasing sequence
def check(arr, n):
 
    flag = True;
 
    # Loop to check that each element
    # is greater than the (N - index)
    for i in range(n):
         
        # If element is less than (N - index)
        if (arr[i] < n - i):
            flag = False;
             
    # If array can be converted
    if (flag):
        return True;
    else:
        return False;
 
# Driver Code
if __name__ == '__main__':
     
    arr1 = [ 11, 11, 11, 11 ];
    n1 = len(arr1);
 
    # Function calling
    if (check(arr1, n1)):
        print("Yes");
    else:
        print("No");
 
# This code is contributed by sapnasingh4991

C#

// C# implementation to check that
// array can be converted into a
// strictly decreasing sequence
using System;
 
class GFG{
 
// Function to check that array
// can be converted into a
// strictly decreasing sequence
static bool check(int []arr, int n)
{
    bool flag = true;
 
    // Loop to check that each element is
    // greater than the (N - index)
    for(int i = 0; i < n; i++)
    {
 
       // If element is less than (N - index)
       if (arr[i] < n - i)
       {
           flag = false;
       }
    }
 
    // If array can be converted
    if (flag)
    {
        return true;
    }
    else
    {
        return false;
    }
}
 
// Driver Code
static public void Main(String[] args)
{
    int []arr1 = { 11, 11, 11, 11 };
    int n1 = arr1.Length;
 
    // Function calling
    if (check(arr1, n1))
    {
        Console.Write("Yes" + "\n");
    }
    else
    {
        Console.Write("No" + "\n");
    }
}
}
 
// This code is contributed by 29AjayKumar

输出：

Yes

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