使用 STL 从字符串删除所有出现的字符

给定一个字符串S和一个字符C ，任务是从给定的字符串删除所有出现的字符C 。

例子：

Input:vS = “GFG IS FUN”, C = ‘F’
Output:GG IS UN
Explanation:
Removing all occurrences of the character ‘F’ modifies S to “GG IS UN”.
Therefore, the required output is GG IS UN

Input: S = “PLEASE REMOVE THE SPACES”, C = ‘ ‘
Output: PLEASEREMOVETHESPACES
Explanation:
Removing all occurrences of the character ‘ ‘ modifies S to “GG IS UN”.

方法：想法是使用C++ STL中的erase()方法和remove()函数。下面是从字符串删除所有出现的字符的语法。

S.erase(remove(S.begin(), S.end(), c), S.end())

下面是上述方法的实现：

C++

// C++ program of the above approach
#include 
#include 
using namespace std;
  
// Function to remove all occurences
// of C from the string S
string removeCharacters(string S, char c)
{
  
    S.erase(remove(
                S.begin(), S.end(), c),
            S.end());
  
    return S;
}
  
// Driver Code
int main()
{
  
    // Given String
    string S = "GFG is Fun";
    char C = 'F';
    cout << "String Before: " << S << endl;
  
    // Function call
    S = removeCharacters(S, C);
  
    cout << "String After: " << S << endl;
    return 0;
}

输出：

String Before: GFG is Fun
String After: GG is un

时间复杂度： O(N ² )
辅助空间： O(1)

如果您想与行业专家一起参加直播课程，请参阅Geeks Classes Live