📜  画一个没有浮点运算的圆

📅  最后修改于: 2021-10-23 07:28:33             🧑  作者: Mango

给定一个圆的半径,在不使用浮点运算的情况下绘制圆。
以下程序使用了一个简单的概念。设圆的半径为r。考虑围绕要绘制的圆的大小为 (2r+1)*(2r+1) 的正方形。现在走过广场内的每个点。对于每个点 (x,y),如果 (x, y) 位于圆内(或 x^2+ y^2 < r^2),则打印它,否则打印空间。

C++
// C++ code to demonstrate to draw
// circle without floating
// point arithmetic
#include 
 
void drawCircle(int r)
{
    // Consider a rectangle of size N*N
    int N = 2*r+1;
 
    int x, y;  // Coordinates inside the rectangle
 
    // Draw a square of size N*N.
    for (int i = 0; i < N; i++)
    {
        for (int j = 0; j < N; j++)
        {
            // Start from the left most corner point
            x = i-r;
            y = j-r;
 
            // If this point is inside the circle, print it
            if (x*x + y*y <= r*r+1 )
                printf(".");
            else // If outside the circle, print space
                printf(" ");
            printf(" ");
        }
        printf("\n");
    }
}
 
// Driver Program to test above function
int  main()
{
    drawCircle(8);
    return 0;
}


Java
// Java code to demonstrate to draw
// circle without floating
// point arithmetic
 
class GFG
{
static void drawCircle(int r)
{
    // Consider a rectangle of size N*N
    int N = 2*r+1;
 
    int x, y; // Coordinates inside the rectangle
 
    // Draw a square of size N*N.
    for (int i = 0; i < N; i++)
    {
        for (int j = 0; j < N; j++)
        {
            // Start from the left most corner point
            x = i-r;
            y = j-r;
 
            // If this point is inside the circle, print it
            if (x*x + y*y <= r*r+1 )
                System.out.print(".");
            else
                // If outside the circle, print space
                System.out.print(" ");
 
            System.out.print(" ");
        }
 
        System.out.println();
    }
}
 
// Driver Program to test above function
public static void main(String arg[])
{
    drawCircle(8);
}
}
 
// This code is contributed
// by Anant Agarwal.


Python3
# Python3 code to demonstrate to draw
# circle without floating
# point arithmetic
 
def drawCircle(r):
 
    # Consider a rectangle of size N*N
    N = 2 * r + 1
 
    # Draw a square of size N*N.
    for i in range(N):
        for j in range(N):
 
            # Start from the left most corner point
            x = i - r
            y = j - r
 
            # If this point is inside the circle,
            # print it
            if x * x + y * y <= r * r + 1:
                print(".", end = " ")
                 
            # If outside the circle, print space
            else:
                print(" ", end = " ")
        print()
 
# Driver Code
if __name__ == "__main__":
    drawCircle(8)
 
# This code is contributed
# by vibhu4agarwal


C#
// C# code to demonstrate to draw
// circle without floating
// point arithmetic
using System;
 
public class GFG{
    static void drawCircle(int r)
{
    // Consider a rectangle of size N*N
    int N = 2*r+1;
 
    int x, y; // Coordinates inside the rectangle
 
    // Draw a square of size N*N.
    for (int i = 0; i < N; i++)
    {
        for (int j = 0; j < N; j++)
        {
            // Start from the left most corner point
            x = i-r;
            y = j-r;
 
            // If this point is inside the circle, print it
            if (x*x + y*y <= r*r+1 )
                Console.Write(".");
            else
                // If outside the circle, print space
                Console.Write(" ");
 
            Console.Write(" ");
        }
 
        Console.WriteLine();
    }
}
 
// Driver Program to test above function
    static public void Main (){
        drawCircle(8);
     
      
    }
// This code is contributed
// by ajit.
}


PHP


Javascript


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