正七边形的对角线

给定一个正七边形边的整数a ，任务是找到并打印其对角线的长度。

例子：

Input: a = 6 
Output: 10.812
Input: a = 9 
Output: 16.218 
 

方法：我们知道多边形的内角和 = (n – 2) * 180其中， n是第一个。多边形中的边数。
因此，七边形的内角之和 = 5 * 180 = 900 ，每个内角将是128.58 （约）。
现在，我们必须找到BC = 2 * x 。如果我们在BC上画一条垂直的AO ，我们将看到BO和OC 中的BC的垂直平分线，因为三角形AOB和AOC彼此全等。
所以，在三角形AOB 中， sin(64.29) = x / a即x = 0.901 * a
因此，对角线长度将为2 * x即1.802 * a 。
下面是上述方法的实现：

C++

// C++ Program to find the diagonal
// of a regular heptagon
#include 
using namespace std;
 
// Function to return the diagonal
// of a regular heptagon
float heptdiagonal(float a)
{
 
    // Side cannot be negative
    if (a < 0)
        return -1;
 
    // Length of the diagonal
    float d = 1.802 * a;
    return d;
}
 
// Driver code
int main()
{
    float a = 6;
    cout << heptdiagonal(a) << endl;
    return 0;
}

Java

// Java program to find the diagonal of a regular heptagon
import java.util.*;
import java.lang.*;
import java.io.*;
 
public class GFG {
 
    // Function to return the diagonal of a regular heptagon
    static double heptdiagonal(double a)
    {
 
//side cannot be negative
        if(a<0)
        return -1;
 
        // length of the diagonal
        double d=1.802*a;
         
        return d;
    }
 
    // Driver code
    public static void main(String[] args)
    {
        int a = 6;
        System.out.println(heptdiagonal(a));
    }
}

Python3

# Python3 Program to find the diagonal
# of a regular heptagon
 
# Function to return the diagonal
# of a regular heptagon
def heptdiagonal(a) :
 
    # Side cannot be negative
    if (a < 0) :
        return -1
 
    # Length of the diagonal
    d = 1.802 * a
     
    return round(d, 3)
 
# Driver code
if __name__ == "__main__" :
 
    a = 6
    print(heptdiagonal(a))
 
# This code is contributed by Ryuga

C#

// C# program to find the diagonal of a regular heptagon
using System;
public class GFG {
 
    // Function to return the diagonal of a regular heptagon
    static double heptdiagonal(double a)
    {
 
//side cannot be negative
        if(a<0)
        return -1;
 
        // length of the diagonal
        double d=1.802*a;
         
        return d;
    }
 
    // Driver code
    public static void Main()
    {
        int a = 6;
        Console.WriteLine(heptdiagonal(a));
    }
} // This code is contributed by Mukul singh

---

Javascript

// javascript program to find the diagonal of a regular heptagon
 
    // Function to return the diagonal of a regular heptagon
    function heptdiagonal(a)
    {
 
        // side cannot be negative
        if(a < 0)
        return -1;
 
        // length of the diagonal
        var d = 1.802*a;
         
        return d;
    }
 
// Driver code
var a = 6;
document.write(heptdiagonal(a).toFixed(5));
 
// This code contributed by Princi Singh

输出：

10.812

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