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📜  在 Golang 中找到复数的反双曲正切

📅  最后修改于: 2021-10-25 02:35:43             🧑  作者: Mango

Go 语言在 cmplx 包的帮助下为复数的基本常量和数学函数提供了内置支持。您可以借助 math/cmplx 包提供的Atanh()函数找到指定复数的反双曲正切值。因此,您需要借助 import 关键字在程序中添加一个 math/cmplx 包来访问 Atanh()函数。

句法:

func Atanh(x complex128) complex128

让我们在给定示例的帮助下讨论这个概念:

示例 1:

// Golang program to illustrate how to find the
// Inverse Hyperbolic Tangent of Complex Number
  
package main
  
import (
    "fmt"
    "math/cmplx"
)
  
// Main function
func main() {
  
    // Finding the inverse hyperbolic tangent 
    // of the specified complex number
    // Using Atanh() function
    res_1 := cmplx.Atanh(2 + 5i)
    res_2 := cmplx.Atanh(-9 + 8i)
    res_3 := cmplx.Atanh(-5 - 7i)
  
    // Displaying the result
    fmt.Println("Result 1:", res_1)
    fmt.Println("Result 2:", res_2)
    fmt.Println("Result 3:", res_3)
}

输出:

Result 1: (0.06706599664866984+1.3992843565845448i)
Result 2: (-0.0619590409761453+1.5154677162079488i)
Result 3: (-0.06706599664866986-1.4760562478543229i)

示例 2:

// Golang program to illustrate how to find
// Inverse Hyperbolic Tangent of Complex Number
package main
  
import (
    "fmt"
    "math/cmplx"
)
  
// Main function
func main() {
  
    cnumber_1 := complex(5, 7)
    cnumber_2 := complex(6, 9)
  
    // Finding inverse hyperbolic tangent
    cvalue_1 := cmplx.Atanh(cnumber_1)
    cvalue_2 := cmplx.Atanh(cnumber_2)
  
    // Sum of two inverse hyperbolic tangent values
    res := cvalue_1 + cvalue_2
  
    // Displaying results
    fmt.Println("Complex Number 1: ", cnumber_1)
    fmt.Println("Inverse hyperbolic tangent 1: ", cvalue_1)
  
    fmt.Println("Complex Number 2: ", cnumber_2)
    fmt.Println("Inverse hyperbolic tangent 2: ", cvalue_2)
    fmt.Println("Sum of inverse hyperbolic tangents : ", res)
  
}

输出:

Complex Number 1:  (5+7i)
Inverse hyperbolic tangent 1:  (0.06706599664866984+1.4760562478543229i)
Complex Number 2:  (6+9i)
Inverse hyperbolic tangent 2:  (0.051023839085878805+1.4938239945657217i)
Sum of inverse hyperbolic tangents :  (0.11808983573454865+2.969880242420045i)