红宝石 |日期 ajd() 方法
Date#ajd()是一个 Date 类方法，它返回天文儒略日数。
Syntax: Date.ajd()
Parameter: Date values
Return: the astronomical Julian day number.
示例 #1：
# Ruby code for Date.ajd() method
# loading date
require 'date'
# declaring Date
a = Date.new(2019, 1, 1)
# declaring Date
b = Date.jd(2452004)
# declaring Date
c = Date.ordinal(2019, 12)
# Date
puts "Date a : #{a}\n\n"
puts "Date b : #{b}\n\n"
puts "Date c : #{c}\n\n\n\n"
# ajd form
puts "Date a ajd form : #{a.ajd}\n\n"
puts "Date b ajd form : #{b.ajd}\n\n"
puts "Date c ajd form : #{c.ajd}\n\n"
输出 ：
Date a : 2019-01-01
Date b : 2001-04-04
Date c : 2019-01-12
Date a ajd form : 4916969/2
Date b ajd form : 4904007/2
Date c ajd form : 4916991/2
示例 #2：
# Ruby code for Date.ajd() method
# loading date
require 'date'
# declaring Date
a = Date.parse('2019-01-01')
# declaring Date
b = Date.strptime('03-12-2019', '%d-%m-%Y')
# declaring Date
c = Date.commercial(2019, 5, 6)
# Date
puts "Date a : #{a}\n\n"
puts "Date b : #{b}\n\n"
puts "Date c : #{c}\n\n\n\n"
# ajd form
puts "Date a ajd form : #{a.ajd}\n\n"
puts "Date b ajd form : #{b.ajd}\n\n"
puts "Date c ajd form : #{c.ajd}\n\n"
输出 ：
Date a : 2019-01-01
Date b : 2019-12-03
Date c : 2019-02-02
Date a ajd form : 4916969/2
Date b ajd form : 4917641/2
Date c ajd form : 4917033/2