Python程序从字符串列表中提取给定范围内的字符

给定一个字符串列表，提取跨越整个字符串列表的索引范围内的字符。

Input : test_list = [“geeksforgeeks”, “is”, “best”, “for”, “geeks”], strt, end = 14, 20 
Output : sbest 
Explanation : Once concatenated, 14 – 20 range is extracted.

Input : test_list = [“geeksforgeeks”, “is”, “best”, “for”, “geeks”], strt, end = 11, 20 
Output : sbesbest 
Explanation : Once concatenated, 11 – 20 range is extracted. 
 

方法 1：使用 join() + 列表理解

在此，我们使用 join() 和列表理解执行所有字符串的连接，然后发布，提取所需的字符范围。

Python3

# initializing list
test_list = ["geeksforgeeks", "is", "best", "for", "geeks"]
  
# printing original list
print("The original list is : " + str(test_list))
  
# initializing char range 
strt, end = 14, 30
  
# strt and end used to get desired characters
res = ''.join([sub for sub in test_list])[strt : end]
  
# printing result 
print("Range characters : " + str(res))

输出

The original list is : ['geeksforgeeks', 'is', 'best', 'for', 'geeks']
Range characters : sbestforgeeks

方法 2：使用 chain.from_iterable() + join()

在此，我们使用 chain.from_iterable() 执行扁平化字符的任务，之后使用 join() 连接所有字符串并在范围内提取索引。

蟒蛇3

# import module
from itertools import chain
  
# initializing list
test_list = ["geeksforgeeks", "is", "best", "for", "geeks"]
  
# printing original list
print("The original list is : " + str(test_list))
  
# initializing char range 
strt, end = 14, 30
  
# strt and end used to get desired characters
res = ''.join(chain.from_iterable(test_list))[strt : end]
  
# printing result 
print("Range characters : " + str(res))

输出

The original list is : ['geeksforgeeks', 'is', 'best', 'for', 'geeks']
Range characters : sbestforgeeks