返回程序

def compare_min_frequency(first_sentence, second_sentence):
    """
    This function compares the frequency of the smallest character in two given sentences.
    :param first_sentence: the first sentence to compare
    :param second_sentence: the second sentence to compare
    :return: a boolean indicating whether the frequency of the smallest character in the first sentence
             is smaller than that in the second sentence
    """
    # Get the smallest character in each sentence
    min_char_first = min(first_sentence)
    min_char_second = min(second_sentence)
    
    # Count the frequency of the smallest character in each sentence
    frequency_first = first_sentence.count(min_char_first)
    frequency_second = second_sentence.count(min_char_second)
    
    # Compare the frequency of the smallest character in each sentence
    if frequency_first < frequency_second:
        return True
    else:
        return False

算法思路

1. 通过内置函数min()获取每个字符串中的最小字符。
2. 通过字符串方法count()获取每个字符串中最小字符的频率。
3. 比较两个字符串中最小字符的频率，判断是否满足题目所述条件。

示例使用

result = compare_min_frequency('hello', 'world')
print(result)  # True

返回说明

返回的程序实现了题目的要求，通过两个字符串中的最小字符及其频率进行比较，返回结果为布尔值表示两个字符串中最小字符的频率大小关系。使用者可以通过调用compare_min_frequency()函数并传入两个待比较字符串，获得比较结果并进行后续操作。如果结果为True，则表示第一个字符串中最小字符的频率小于第二个字符串中最小字符的频率，否则表示不满足条件。