📅  最后修改于: 2022-03-11 15:04:56.689000             🧑  作者: Mango
/** Find the higher id values of duplicates, distinct only added for clarity */
SELECT distinct d2.id
FROM dupes d1
INNER JOIN dupes d2 ON d2.word=d1.word AND d2.num=d1.num
WHERE d2.id > d1.id
/*
id|
--|
5|
6|
8|
9|
10|
*/
/** Use the previous query in a subquery to exclude the dupliates with higher id values */
SELECT *
FROM dupes
WHERE id NOT IN (
SELECT d2.id
FROM dupes d1
INNER JOIN dupes d2 ON d2.word=d1.word AND d2.num=d1.num
WHERE d2.id > d1.id
)
ORDER BY word, num;
/*
word|num|id|
----|---|--|
aaa |100| 1|
bbb |200| 2|
bbb |400| 4|
ccc |300| 3|
ddd |400| 7|
*/