📅  最后修改于: 2020-11-16 07:18:04             🧑  作者: Mango
使用JSON.simple,我们可以使用以下方式对JSON对象进行编码-
将JSON对象编码-字符串-简单编码。
编码JSON对象-流-输出可用于流。
编码JSON对象-使用Map-通过保留顺序进行编码。
编码JSON对象-使用Map和Streaming-通过保留顺序和流进行编码。
以下示例说明了上述概念。
import java.io.IOException;
import java.io.StringWriter;
import java.util.LinkedHashMap;
import java.util.Map;
import org.json.simple.JSONObject;
import org.json.simple.JSONValue;
class JsonDemo {
public static void main(String[] args) throws IOException {
JSONObject obj = new JSONObject();
String jsonText;
obj.put("name", "foo");
obj.put("num", new Integer(100));
obj.put("balance", new Double(1000.21));
obj.put("is_vip", new Boolean(true));
jsonText = obj.toString();
System.out.println("Encode a JSON Object - to String");
System.out.print(jsonText);
StringWriter out = new StringWriter();
obj.writeJSONString(out);
jsonText = out.toString();
System.out.println("\nEncode a JSON Object - Streaming");
System.out.print(jsonText);
Map obj1 = new LinkedHashMap();
obj1.put("name", "foo");
obj1.put("num", new Integer(100));
obj1.put("balance", new Double(1000.21));
obj1.put("is_vip", new Boolean(true));
jsonText = JSONValue.toJSONString(obj1);
System.out.println("\nEncode a JSON Object - Preserving Order");
System.out.print(jsonText);
out = new StringWriter();
JSONValue.writeJSONString(obj1, out);
jsonText = out.toString();
System.out.println("\nEncode a JSON Object - Preserving Order and Stream");
System.out.print(jsonText);
}
}
Encode a JSON Object - to String
{"balance":1000.21,"is_vip":true,"num":100,"name":"foo"}
Encode a JSON Object - Streaming
{"balance":1000.21,"is_vip":true,"num":100,"name":"foo"}
Encode a JSON Object - Preserving Order
{"name":"foo","num":100,"balance":1000.21,"is_vip":true}
Encode a JSON Object - Preserving Order and Stream
{"name":"foo","num":100,"balance":1000.21,"is_vip":true}