红宝石 |整数 upto()函数

Ruby 中的upto函数将给定的所有数字返回到数字本身。它迭代给定的块，传入从 number1 到 number2 的递增值。如果没有给出块，则返回一个枚举器。

Syntax: (number1).upto(number2)

Parameter: The function takes number1 and number2 which is the range in which the numbers are returned. It also takes a block. 

Return Value: The function returns all the numbers from number1 to number2 itself.

示例 1 ：

Ruby

#Ruby program for upto() function
 
#Initializing the number
num1 = 8 num2 = 12
 
#Prints the number from num1 to num2
                puts num1.upto(num2)
{
    | i | print i, " "
}
 
#Initializing the number
num3 = 5 num4 = 15
 
#Prints the number from num3 to num4
                puts num3.upto(num4)
{
    | i | print i, " "
}

输出：

8 9 10 11 12 8
5 6 7 8 9 10 11 12 13 14 15 5

示例 2 ：

红宝石

#Ruby program for upto() function
 
#Initializing the number
num1 = 1 num2 = 3
 
#Prints the number from num1 to num2
                puts num1.upto(num2)
{
    | i | print i, " "
}
 
#Initializing the number
num3 = -7 num4 = -2
 
#Prints the number from num3 to num4
                  puts num3.upto(num4)
{
    | i | print i, " "
}

输出：

1 2 3 1
-7 -6 -5 -4 -3 -2 -7

示例 3 ：

红宝石

#Ruby program for upto() function
 
#Initializing the number
num1 = 1 num2 = 3
 
#Returns an enumerator
#since no block is passed
                puts num1.upto(num2)

输出：

#

参考：https://devdocs.io/ruby~2.5/integer#method-i-upto