如何在 C++ STL 中使用列表实现堆栈
在本文中,我们将讨论如何在 C++ STL 中使用列表来实现堆栈。
堆栈是一种线性数据结构。 LIFO(后进先出)或 FILO(先进后出)。主要支持4大操作:
1. Push:将一个元素压入栈中。
2.弹出:按照LIFO顺序删除元素。
3. Top:返回栈顶元素。
4. Empty:返回栈是否为空。
下面是上述方法的实现:
C++
// C++ implementation of stack
// using list STL
#include
using namespace std;
template
// templating it so that any data type can be used
class Stack {
public:
list l;
int cs = 0;
// current size of the stack
// pushing an element into the stack
void push(T d)
{
cs++;
// increasing the current size of the stack
l.push_front(d);
}
// popping an element from the stack
void pop()
{
if (cs <= 0) {
// cannot pop us stack does not contain an
// elements
cout << "Stack empty" << endl;
}
else {
// decreasing the current size of the stack
cs--;
l.pop_front();
}
}
// if current size is 0 then stack is empty
bool empty() { return cs == 0; }
// getting the element present at the top of the stack
T top() { return l.front(); }
int size()
{
// getting the size of the stack
return cs;
}
// printing the elements of the stack
void print()
{
for (auto x: l) {
cout << x << endl;
}
}
};
int main()
{
Stack s;
s.push(10); // pushing into the stack
s.push(20);
s.push(30);
s.push(40);
cout << "Current size of the stack is " << s.size()
<< endl;
cout << "The top element of the stack is " << s.top()
<< endl;
s.pop(); // popping from the stack
cout << "The top element after 1 pop operation is "
<< s.top()
<< endl; // printing the top of the stack
s.pop(); // popping
cout << "The top element after 2 pop operations is "
<< s.top() << endl;
cout << "Size of the stack after 2 pop operations is "
<< s.size() << endl;
return 0;
}
输出
Current size of the stack is 4
The top element of the stack is 40
The top element after 1 pop operation is 30
The top element after 2 pop operations is 20
Size of the stack after 2 pop operations is 2
时间复杂度:对于堆栈中的入栈和出栈操作来说都是 O(1)。
辅助空间: O(N)
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