Python| os.path.samefile() 方法

Python中的OS 模块提供了与操作系统交互的功能。操作系统属于 Python 的标准实用程序模块。该模块提供了一种使用操作系统相关功能的可移植方式。 os.path模块是Python中OS 模块的子模块，用于常见的路径名操作。

Python中的os.path.samefile()方法用于检查给定的两个路径名是否引用相同的文件或目录。这是通过比较给定路径的设备号和 i 节点号来确定的。
该方法利用os.stat()方法获取给定路径的设备号和 i-node 号。因此，如果os.stat()调用在任一路径名上失败，则会引发异常。

Syntax: os.path.samefile(path1, path2)

Parameter:
path1: A path-like object representing the first file system path.
path2: A path-like object representing the second file system path.

A path-like object is either a string or bytes object representing a path.

Return Type: This method returns a Boolean value of class bool. This method returns True if both path refer to the same file otherwise returns False.

编程需要懂一点英语

代码：使用 os.path.samefile() 方法检查给定路径是否引用相同的文件或目录。

# Python program to explain os.path.samefile() method 
    
# importing os module 
import os
  
# Path
path1 = "/home / ihritik / Documents / file(original).txt"
  
# Create a symbolic link 
sym_link = "/home / ihritik / Desktop / file(shortcut).txt"
os.symlink(path1, sym_link)
  
# Check whether the given
# paths refer to the same
# file or directory or not
areSame = os.path.samefile(path1, sym_link)
  
# Print the result
print(areSame)
  
# In above example, sym_link is 
# a symbolic link which refers
# to path1, so os.path.samefile() method
# will return True as both refer 
# to same file
  
  
# First Path
path2 = "/home / ihritik / GeeksForGeeks"
  
# Second path
# consider the current working directory
# is "/home / ihritik"
path3 = os.path.join(os.getcwd(), "GeeksForGeeks")
  
# Check whether the given
# paths refer to the same
# file or directory or not
areSame = os.path.samefile(path2, path3)
  
# Print the result
print(areSame)

输出：

True
True

参考： https://docs。 Python.org/3/library/os.path.html