📜  OS Binary Semaphore或Mutex

📅  最后修改于: 2020-12-14 03:47:08             🧑  作者: Mango

二进制信号量或互斥量

在计算信号量时,未提供互斥,因为我们有一组必须在关键部分同时执行的过程。

但是,Binary Semaphore严格提供互斥。在这里,关键部分中最多只能有1个进程,而不是关键部分中有1个以上的可用插槽。信号量只能有两个值,即0或1。

让我们看一下二进制信号量的编程实现。

StructBsemaphore
{
    enum Value(0,1); //value is enumerated data type which can only have two values 0 or 1.
    Queue type L;
}
/* L contains all PCBs corresponding to process 
Blocked while processing down operation unsuccessfully. 
*/ 
Down (Bsemaphore S) 
{
    if (s.value == 1) // if a slot is available in the 
    //critical section then let the process enter in the queue. 
    {
        S.value = 0; // initialize the value to 0 so that no other process can read it as 1. 
    }
    else
    {
        put the process (PCB) in S.L; //if no slot is available 
        //then let the process wait in the blocked queue. 
        sleep(); 
    }
}
Up (Bsemaphore S) 
{
    if (S.L is empty) //an empty blocked processes list implies that no process 
    //has ever tried to get enter in the critical section. 
    {
        S.Value =1; 
    }
    else
    {
        Select a process from S.L; 
        Wakeup(); // if it is not empty then wake the first process of the blocked queue. 
    } 
}