Java中的整数reverse()方法
Java.lang.Integer.reverse() 是Java中的一个内置方法,用于返回指定int 值的二进制补码二进制表示中位的倒序。
句法:
public static int reverse(int a)
参数:参数a是一个整数值,其位将被反转。
返回值:该方法返回将指定int值中位的顺序颠倒得到的值。
例子:
Input: 86
Output: 1778384896
Explanation:
Consider an integer a = 86
Binary Representation = 1010110
The number of one bit = 4
After reversing it is = 1778384896
Input: 168
Output: 352321536
下面的程序说明了Java.lang.Integer.reverse() 方法:
程序 1:对于正数。
// Java program to illustrate the
// Java.lang.Integer.reverse() method
import java.lang.*;
public class geeks {
public static void main(String[] args)
{
int a = 168;
System.out.println("Number = " + a);
// It returns the value obtained by reversing order of the bits
System.out.println("By reversing we get = " + Integer.reverse(a));
}
}
输出:
Number = 168
By reversing we get = 352321536
程序 2:对于负数。
// Java program to illustrate the
// Java.lang.Integer.reverse() method
import java.lang.*;
public class geeks {
public static void main(String[] args)
{
int a = -72;
System.out.println("Number = " + a);
// It returns the value obtained by reversing order of the bits
System.out.println("By reversing we get = " + Integer.reverse(a));
}
}
输出:
Number = -72
By reversing we get = 503316479
程序 3:对于十进制值和字符串。
注意:当十进制值或字符串作为参数传递时,它会引发错误消息。
// Java program to illustrate the
// Java.lang.Integer.reverse() method
import java.lang.*;
public class geeks {
public static void main(String[] args)
{
int a = 37.9;
System.out.println("Number = " + a);
// It returns the value obtained by reversing order of the bits in
// the specified int value
System.out.println("By reversing we get = " + Integer.reverse(a));
a = "21";
System.out.println("Number = " + a);
// It returns the value obtained by reversing order of the bits in
// the specified int value
System.out.println("By reversing we get = " + Integer.reverse(a));
}
}
输出:
prog.java:9: error: incompatible types: possible lossy conversion from double to int
int a = 37.9;
^
prog.java:17: error: incompatible types: String cannot be converted to int
a = "21";
^
2 errors