Python – 将列表转换为字典列表
给定列表值和键列表，将这些值转换为字典列表形式的键值对。
Input : test_list = [“Gfg”, 3, “is”, 8], key_list = [“name”, “id”]
Output : [{‘name’: ‘Gfg’, ‘id’: 3}, {‘name’: ‘is’, ‘id’: 8}]
Explanation : Values mapped by custom key, “name” -> “Gfg”, “id” -> 3.
Input : test_list = [“Gfg”, 10], key_list = [“name”, “id”]
Output : [{‘name’: ‘Gfg’, ‘id’: 10}]
Explanation : Conversion of lists to list of records by keys mapping.
方法#1：使用循环+字典理解
这是可以执行此任务的方式之一。在此，我们使用字典理解执行映射值。使用循环执行迭代。
Python3
# Python3 code to demonstrate working of
# Convert List to List of dictionaries
# Using dictionary comprehension + loop
# initializing lists
test_list = ["Gfg", 3, "is", 8, "Best", 10, "for", 18, "Geeks", 33]
# printing original list
print("The original list : " + str(test_list))
# initializing key list
key_list = ["name", "number"]
# loop to iterate through elements
# using dictionary comprehension
# for dictionary construction
n = len(test_list)
res = []
for idx in range(0, n, 2):
res.append({key_list[0]: test_list[idx], key_list[1] : test_list[idx + 1]})
# printing result
print("The constructed dictionary list : " + str(res))Python3
# Python3 code to demonstrate working of
# Convert List to List of dictionaries
# Using zip() + list comprehension
# initializing lists
test_list = ["Gfg", 3, "is", 8, "Best", 10, "for", 18, "Geeks", 33]
# printing original list
print("The original list : " + str(test_list))
# initializing key list
key_list = ["name", "number"]
# using list comprehension to perform as shorthand
n = len(test_list)
res = [{key_list[0]: test_list[idx], key_list[1]: test_list[idx + 1]}
for idx in range(0, n, 2)]
# printing result
print("The constructed dictionary list : " + str(res))The original list : [‘Gfg’, 3, ‘is’, 8, ‘Best’, 10, ‘for’, 18, ‘Geeks’, 33]
The constructed dictionary list : [{‘name’: ‘Gfg’, ‘number’: 3}, {‘name’: ‘is’, ‘number’: 8}, {‘name’: ‘Best’, ‘number’: 10}, {‘name’: ‘for’, ‘number’: 18}, {‘name’: ‘Geeks’, ‘number’: 33}]
方法#2：使用字典理解+列表理解
以上功能的组合就是用来解决这个问题的。在此，我们执行与上述方法类似的任务。但不同之处在于它作为速记执行。
Python3
# Python3 code to demonstrate working of
# Convert List to List of dictionaries
# Using zip() + list comprehension
# initializing lists
test_list = ["Gfg", 3, "is", 8, "Best", 10, "for", 18, "Geeks", 33]
# printing original list
print("The original list : " + str(test_list))
# initializing key list
key_list = ["name", "number"]
# using list comprehension to perform as shorthand
n = len(test_list)
res = [{key_list[0]: test_list[idx], key_list[1]: test_list[idx + 1]}
for idx in range(0, n, 2)]
# printing result
print("The constructed dictionary list : " + str(res))
The original list : [‘Gfg’, 3, ‘is’, 8, ‘Best’, 10, ‘for’, 18, ‘Geeks’, 33]
The constructed dictionary list : [{‘name’: ‘Gfg’, ‘number’: 3}, {‘name’: ‘is’, ‘number’: 8}, {‘name’: ‘Best’, ‘number’: 10}, {‘name’: ‘for’, ‘number’: 18}, {‘name’: ‘Geeks’, ‘number’: 33}]