Python - 找出 Matrix 中缺失的列表元素总和的差，反之亦然

给定一个列表和一个 Matrix，任务是编写一个Python程序，该程序可以找到 Matrix 中缺少的列表元素之和的差，反之亦然。

一个更简单的解释是，找到并求和在 Matrix 中找到但不在列表中的所有元素。接下来，查找并求和列表中找到的所有不在矩阵中的元素。执行提取的总和值之间的差异。

Input : test_list = [[2, 4, 1], [8, 1, 2], [9, 1, 10], [4, 3, 2]], tar_list = [2, 3, 10, 7, 5, 4] 
Output : 8 
Explanation : 8 + 9 + 1 + 1 + 1 = 20 [ Elements in Matrix, not in list ]
7 + 5 = 12 [ Elements in list, not in Matrix ]
Difference = 12 – 20 = 8.
 

Input : test_list = [[2], [8], [9], [4]], tar_list = [2, 3, 10, 7, 5, 4] 
Output : 8 
Explanation : 8 + 9 = 17 [ Elements in Matrix, not in list ]
3 + 10 + 7 + 5 = 25 [ Elements in list, not in Matrix ]
Difference = 25 – 17 = 8.
 

方法 1：使用循环和from_iterable()

在这种情况下，我们使用循环中的计数器获得列表中存在的元素的列表总和，而不是矩阵，反之亦然，并计算差异。 from_iterable() 用于展平矩阵。

例子：

Python3

# Python3 code to demonstrate working of
# Missing elements difference from Matrix and List
# Using loop
from itertools import chain
  
# initializing list
test_list = [[2, 4, 1], [8, 1, 2], [9, 1, 10], [4, 3, 2]]
  
# printing original list
print("The original list is : " + str(test_list))
  
# initializing target list
tar_list = [2, 3, 10, 7, 5, 4]
  
# flattening Matrix
flat_mat = list(chain.from_iterable(test_list))
  
# getting sum of list elements not in Matrix
list_sum = 0
for ele in tar_list:
    if ele not in flat_mat:
        list_sum += ele
  
# getting sum of Matrix elements not in list
mat_sum = 0
for ele in flat_mat:
    if ele not in tar_list:
        mat_sum += ele
  
# computing difference
res = abs(mat_sum - list_sum)
  
# printing result
print("The computed count : " + str(res))

输出：

The original list is : [[ 2, 4, 1], [8, 1, 2], [8, 1, 2], [9, 1, 10], [4, 3, 2]]

The computed count : 8

方法 2：使用sum()和from_iterable()

在这里，计算求和的任务是使用 sum() 完成的，其余所有功能都以与上述方法相同的方式执行。

例子：

蟒蛇3

# Python3 code to demonstrate working of
# Missing elements difference from Matrix and List
# Using sum() + from_iterable()
from itertools import chain
  
# initializing list
test_list = [[2, 4, 1], [8, 1, 2], [9, 1, 10], [4, 3, 2]]
  
# printing original list
print("The original list is : " + str(test_list))
  
# initializing target list
tar_list = [2, 3, 10, 7, 5, 4]
  
# flattening Matrix
flat_mat = list(chain.from_iterable(test_list))
  
# getting sum of list elements not in Matrix
list_sum = sum([ele for ele in tar_list if ele not in flat_mat])
  
# getting sum of Matrix elements not in list
mat_sum = sum([ele for ele in flat_mat if ele not in tar_list])
  
# computing difference
res = abs(mat_sum - list_sum)
  
# printing result
print("The computed count : " + str(res))

输出：

The original list is : [[2, 4, 1], [8, 1, 2], [9, 1, 10], [4, 3, 2]]

The computed count : 8