Python程序打印列表中元素重复出现的字符串

给定一个字符串列表，编写一个Python程序，提取列表元素中特定值（此处使用 K 描述）出现多次的所有字符串。

例子：

Input : test_list = [“geeksforgeeks”, “best”, “for”, “geeks”], K = ‘e’ 
Output : [‘geeksforgeeks’, ‘geeks’] 
Explanation : geeks and geeksforgeeks have 2 and 4 occurrences of K respectively.

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Input : test_list = [“geeksforgeeks”, “best”, “for”, “geeks”], K = ‘k’ 
Output : [‘geeksforgeeks’] 
Explanation : geeksforgeeks has 2 occurrences of K 
 

方法 1：使用循环和count()

在这里，我们使用计数检查每个字符串中 K 的所有出现，并检查是否有任何字符串的 K 出现次数超过 1 次，如果找到，则提取该字符串。

Python3

# initializing Matrix
test_list = ["geeksforgeeks", "best", "for", "geeks"]
  
# printing original list
print("The original list is : " + str(test_list))
  
# initializing K
K = 'e'
  
res = []
for ele in test_list:
  
    # checking for count greater than 1 (repetitive)
    if ele.count(K) > 1:
        res.append(ele)
  
# printing result
print("Repeated K strings : " + str(res))

输出：

The original list is : [‘geeksforgeeks’, ‘best’, ‘for’, ‘geeks’]

Repeated K strings : [‘geeksforgeeks’, ‘geeks’]

方法 2：使用列表推导和count()

这是此任务的简写解决方案，类似于上述方法，只是使用列表理解来完成迭代使用。

蟒蛇3

# initializing Matrix
test_list = ["geeksforgeeks", "best", "for", "geeks"]
  
# printing original list
print("The original list is : " + str(test_list))
  
# initializing K
K = 'e'
  
# checking for count greater than 1 (repetitive)
# one-liner using list comprehension
res = [ele for ele in test_list if ele.count(K) > 1]
  
# printing result
print("Repeated K strings : " + str(res))

输出：

The original list is : [‘geeksforgeeks’, ‘best’, ‘for’, ‘geeks’]

Repeated K strings : [‘geeksforgeeks’, ‘geeks’]