📜  PHPUnit | assertClassHasAttribute()函数

📅  最后修改于: 2022-05-13 01:57:40.231000             🧑  作者: Mango

PHPUnit | assertClassHasAttribute()函数

assertClassHasAttribute ()函数是 PHPUnit 中的内置函数,用于断言具有特定属性的类。如果类包含提供的属性,则此断言将返回 true,否则返回 false,如果为 true,则返回断言的测试用例得到通过,否则测试用例失败。

语法

assertClassHasAttribute(string $attributeName, string $className[, string $message = ''])

参数:此函数接受三个参数,如上述语法所示。参数说明如下:

  1. $attributeName :此参数表示类要包含的属性的名称。
  2. $className :此参数是一个字符串,作为要搜索属性的类名。
  3. $message :此参数采用字符串值。当测试用例失败时,此字符串消息显示为错误消息。

下面的程序说明了 assertClassHasAttribute()函数:

程序一



assertClassHasAttribute('geeks', "testClass", "testClass doesn't has geeks as attribute") ;
    }
}
  
?>

输出:

PHPUnit 6.5.5 by Sebastian Bergmann and contributors.

F                                                                   1 / 1 (100%)

Time: 21 ms, Memory: 4.00MB

There was 1 failure:

1) GeeksPhpunitTestCase::testNegativeTestcaseForClassHasAttribute
testClass doesn't has geeks as attribute
Failed asserting that class "testClass" has attribute "geeks".

/home/shivam/Documents/geeks/phpunit/abc.php:14

FAILURES!
Tests: 1, Assertions: 1, Failures: 1.

方案二

assertClassHasAttribute('geeks', "testClass", "testClass doesn't has geeks as attribute") ;
    }
}
  
?>
?>

输出:

PHPUnit 6.5.5 by Sebastian Bergmann and contributors.

.                                                                   1 / 1 (100%)

Time: 21 ms, Memory: 4.00MB

OK (1 test, 1 assertion)

注意:要使用 phpunit 运行测试用例,请按照此处的步骤操作。