Python – 连续元组差异

给定元组列表，找到连续元组的索引绝对差。

Input : test_list = [(5, 3), (1, 4), (9, 5), (3, 5)]
Output : [(4, 1), (7, 1), (6, 0)]
Explanation : 5 – 1 = 4, 4 – 3 = 1. hence (4, 1) and so on.

Input : test_list = [(9, 5), (3, 5)]
Output : [(6, 0)]
Explanation : 9 – 3 = 6, 5 – 5 = 0.

方法#1：使用列表推导

这是可以执行此任务的一种方式。在此，我们使用列表理解策略对列表采用蛮力策略，以单行执行此任务。

Python3

# Python3 code to demonstrate working of 
# Consecutive Tuple difference
# Using list comprehension
  
# initializing lists
test_list = [(6, 3), (1, 4), (8, 5), (3, 5)]
  
# printing original list
print("The original list : " + str(test_list))
  
# using list comprehension to perform absolute difference
# using abs() for difference
res = [(abs(test_list[idx + 1][0] - test_list[idx][0]), abs(test_list[idx + 1][1] - test_list[idx][1])) 
      for idx in range(len(test_list) - 1)]
  
# printing result 
print("The extracted list : " + str(res))

输出

The original list : [(6, 3), (1, 4), (8, 5), (3, 5)]
The extracted list : [(5, 1), (7, 1), (5, 0)]

方法#2：使用 tuple() + map() + sub

上述功能的组合可以用来解决这个问题。在此，我们使用 sub 执行减法任务，并使用 map() 将逻辑扩展到整个列表元素。不输出绝对结果。

Python3

# Python3 code to demonstrate working of 
# Consecutive Tuple difference
# Using tuple() + map() + sub
from operator import sub
  
# initializing lists
test_list = [(6, 3), (1, 4), (8, 5), (3, 5)]
  
# printing original list
print("The original list : " + str(test_list))
  
# using loop to iterate elements
# using sub and map() to perform the subtraction to whole elements
res = []
for idx in range(len(test_list) - 1):
    res.append(tuple(map(sub, test_list[idx + 1][0:], test_list[idx][0:])))
      
# printing result 
print("The extracted list : " + str(res))

输出

The original list : [(6, 3), (1, 4), (8, 5), (3, 5)]
The extracted list : [(-5, 1), (7, 1), (-5, 0)]