📜  跳过列表|第3组(搜索和删除)

📅  最后修改于: 2021-04-17 08:18:20             🧑  作者: Mango

在上一篇文章中跳过列表|第2组(插入)讨论了跳过节点的结构以及如何在跳过列表中插入元素。在本文中,我们将讨论如何在跳过列表中搜索和删除元素。

在跳过列表中搜索元素

搜索元素与搜索要在跳过列表中插入元素的地点的方法非常相似。基本想法是-

  1. 下一个节点的键小于搜索键,然后我们继续在相同级别上前进。
  2. 下一个节点的密钥大于要插入的密钥,然后我们将指向当前节点i的指针存储在update [i]处,并向下移动一级并继续我们的搜索。

在最低级别(0),如果最右边元素(update [0])旁边的元素的键等于搜索键,则我们发现键否则失败。
以下是用于搜索元素的伪代码–

Search(list, searchKey)
x := list -> header
-- loop invariant: x -> key  level downto 0 do
    while x -> forward[i] -> key  forward[i]
x := x -> forward[0]
if x -> key = searchKey then return x -> value
else return failure

考虑这个示例,我们要搜索键17-
搜索键

从“跳过”列表中删除元素

删除元素k之前,使用上述搜索算法在“跳过”列表中定位元素。定位元素后,就像我们在单链列表中一样,完成了指针的重新排列以删除元素表单列表。我们从最低级别开始进行重新排列,直到update [i]旁边的元素不是k。

删除元素后,可能会存在没有元素的级别,因此我们也将通过减少“跳过”列表的级别来删除这些级别。以下是删除的伪代码–

Delete(list, searchKey)
local update[0..MaxLevel+1]
x := list -> header
for i := list -> level downto 0 do
    while x -> forward[i] -> key  forward[i]
    update[i] := x
x := x -> forward[0]
if x -> key = searchKey then
    for i := 0 to list -> level do
        if update[i] -> forward[i] ≠ x then break
        update[i] -> forward[i] := x -> forward[i]
    free(x)
    while list -> level > 0 and list -> header -> forward[list -> level] = NIL do
        list -> level := list -> level – 1

考虑这个示例,我们要删除元素6 –
删除

在第3层,删除元素6后没有任何元素(红色箭头)。因此,我们将跳过列表的层数减1。

以下是用于从跳过列表中搜索和删除元素的代码–

C++
// C++ code for searching and deleting element in skip list
  
#include 
using namespace std;
  
// Class to implement node
class Node
{
public:
    int key;
  
    // Array to hold pointers to node of different level 
    Node **forward;
    Node(int, int);
};
  
Node::Node(int key, int level)
{
    this->key = key;
  
    // Allocate memory to forward 
    forward = new Node*[level+1];
  
    // Fill forward array with 0(NULL)
    memset(forward, 0, sizeof(Node*)*(level+1));
};
  
// Class for Skip list
class SkipList
{
    // Maximum level for this skip list
    int MAXLVL;
  
    // P is the fraction of the nodes with level 
    // i pointers also having level i+1 pointers
    float P;
  
    // current level of skip list
    int level;
  
    // pointer to header node
    Node *header;
public:
    SkipList(int, float);
    int randomLevel();
    Node* createNode(int, int);
    void insertElement(int);
    void deleteElement(int);
    void searchElement(int);
    void displayList();
};
  
SkipList::SkipList(int MAXLVL, float P)
{
    this->MAXLVL = MAXLVL;
    this->P = P;
    level = 0;
  
    // create header node and initialize key to -1
    header = new Node(-1, MAXLVL);
};
  
// create random level for node
int SkipList::randomLevel()
{
    float r = (float)rand()/RAND_MAX;
    int lvl = 0;
    while(r < P && lvl < MAXLVL)
    {
        lvl++;
        r = (float)rand()/RAND_MAX;
    }
    return lvl;
};
  
// create new node
Node* SkipList::createNode(int key, int level)
{
    Node *n = new Node(key, level);
    return n;
};
  
// Insert given key in skip list
void SkipList::insertElement(int key)
{
    Node *current = header;
  
    // create update array and initialize it
    Node *update[MAXLVL+1];
    memset(update, 0, sizeof(Node*)*(MAXLVL+1));
  
    /*    start from highest level of skip list
        move the current pointer forward while key 
        is greater than key of node next to current
        Otherwise inserted current in update and 
        move one level down and continue search
    */
    for(int i = level; i >= 0; i--)
    {
        while(current->forward[i] != NULL &&
              current->forward[i]->key < key)
            current = current->forward[i];
        update[i] = current;
    }
  
    /* reached level 0 and forward pointer to 
       right, which is desired position to 
       insert key. 
    */
    current = current->forward[0];
  
    /* if current is NULL that means we have reached
       to end of the level or current's key is not equal
       to key to insert that means we have to insert
       node between update[0] and current node */
    if (current == NULL || current->key != key)
    {
        // Generate a random level for node
        int rlevel = randomLevel();
  
        /* If random level is greater than list's current
           level (node with highest level inserted in 
           list so far), initialize update value with pointer
           to header for further use */
        if(rlevel > level)
        {
            for(int i=level+1;iforward[i] = update[i]->forward[i];
            update[i]->forward[i] = n;
        }
        cout<<"Successfully Inserted key "<= 0; i--)
    {
        while(current->forward[i] != NULL  &&
              current->forward[i]->key < key)
            current = current->forward[i];
        update[i] = current;
    }
  
    /* reached level 0 and forward pointer to 
       right, which is possibly our desired node.*/
    current = current->forward[0];
  
    // If current node is target node
    if(current != NULL and current->key == key)
    {
        /* start from lowest level and rearrange
           pointers just like we do in singly linked list
           to remove target node */
        for(int i=0;i<=level;i++)
        {
            /* If at level i, next node is not target 
               node, break the loop, no need to move 
              further level */
            if(update[i]->forward[i] != current)
                break;
  
            update[i]->forward[i] = current->forward[i];
        }
  
        // Remove levels having no elements 
        while(level>0 &&
              header->forward[level] == 0)
            level--;
         cout<<"Successfully deleted key "<= 0; i--)
    {
        while(current->forward[i] &&
               current->forward[i]->key < key)
            current = current->forward[i];
  
    }
  
    /* reached level 0 and advance pointer to 
       right, which is possibly our desired node*/
    current = current->forward[0];
  
    // If current node have key equal to
    // search key, we have found our target node
    if(current and current->key == key) 
        cout<<"Found key: "<forward[i];
        cout<<"Level "<key<<" ";
            node = node->forward[i];
        }
        cout<<"\n";
    }
};
  
// Driver to test above code
int main()
{
    // Seed random number generator
    srand((unsigned)time(0));
  
    // create SkipList object with MAXLVL and P 
    SkipList lst(3, 0.5);
  
    lst.insertElement(3);
    lst.insertElement(6);
    lst.insertElement(7);
    lst.insertElement(9);
    lst.insertElement(12);
    lst.insertElement(19);
    lst.insertElement(17);
    lst.insertElement(26);
    lst.insertElement(21);
    lst.insertElement(25);
    lst.displayList();
  
    //Search for node 19
    lst.searchElement(19);
  
    //Delete node 19
    lst.deleteElement(19);
    lst.displayList();
}


Python
# Python3 code for searching and deleting element in skip list
  
import random
  
class Node(object):
    '''
    Class to implement node
    '''
    def __init__(self, key, level):
        self.key = key
  
        # list to hold references to node of different level 
        self.forward = [None]*(level+1)
  
class SkipList(object):
    '''
    Class for Skip list
    '''
    def __init__(self, max_lvl, P):
        # Maximum level for this skip list
        self.MAXLVL = max_lvl
  
        # P is the fraction of the nodes with level 
        # i references also having level i+1 references
        self.P = P
  
        # create header node and initialize key to -1
        self.header = self.createNode(self.MAXLVL, -1)
  
        # current level of skip list
        self.level = 0
      
    # create  new node
    def createNode(self, lvl, key):
        n = Node(key, lvl)
        return n
      
    # create random level for node
    def randomLevel(self):
        lvl = 0
        while random.random() self.level:
                for i in range(self.level+1, rlevel+1):
                    update[i] = self.header
                self.level = rlevel
  
            # create new node with random level generated
            n = self.createNode(rlevel, key)
  
            # insert node by rearranging references 
            for i in range(rlevel+1):
                n.forward[i] = update[i].forward[i]
                update[i].forward[i] = n
  
            print("Successfully inserted key {}".format(key))
  
    def deleteElement(self, search_key):
  
        # create update array and initialize it
        update = [None]*(self.MAXLVL+1)
        current = self.header
  
        '''
        start from highest level of skip list
        move the current reference forward while key 
        is greater than key of node next to current
        Otherwise inserted current in update and 
        move one level down and continue search
        '''
        for i in range(self.level, -1, -1):
            while(current.forward[i] and \
                  current.forward[i].key < search_key):
                current = current.forward[i]
            update[i] = current
  
        ''' 
        reached level 0 and advance reference to 
        right, which is prssibly our desired node
        ''' 
        current = current.forward[0]
  
        # If current node is target node
        if current != None and current.key == search_key:
  
            '''
            start from lowest level and rearrange references 
            just like we do in singly linked list
            to remove target node
            '''
            for i in range(self.level+1):
  
                '''
                If at level i, next node is not target 
                node, break the loop, no need to move 
                further level
                '''
                if update[i].forward[i] != current:
                    break
                update[i].forward[i] = current.forward[i]
  
            # Remove levels having no elements
            while(self.level>0 and\
                  self.header.forward[self.level] == None):
                self.level -= 1
            print("Successfully deleted {}".format(search_key))
  
    def searchElement(self, key): 
        current = self.header
  
        '''
        start from highest level of skip list
        move the current reference forward while key 
        is greater than key of node next to current
        Otherwise inserted current in update and 
        move one level down and continue search
        '''
        for i in range(self.level, -1, -1):
            while(current.forward[i] and\
                  current.forward[i].key < key):
                current = current.forward[i]
  
        # reached level 0 and advance reference to 
        # right, which is prssibly our desired node
        current = current.forward[0]
  
        # If current node have key equal to
        # search key, we have found our target node
        if current and current.key == key:
            print("Found key ", key)
  
  
    # Display skip list level wise
    def displayList(self):
        print("\n*****Skip List******")
        head = self.header
        for lvl in range(self.level+1):
            print("Level {}: ".format(lvl), end=" ")
            node = head.forward[lvl]
            while(node != None):
                print(node.key, end=" ")
                node = node.forward[lvl]
            print("")
  
# Driver to test above code
def main():
    lst = SkipList(3, 0.5)
    lst.insertElement(3)
    lst.insertElement(6)
    lst.insertElement(7)
    lst.insertElement(9)
    lst.insertElement(12)
    lst.insertElement(19)
    lst.insertElement(17)
    lst.insertElement(26)
    lst.insertElement(21)
    lst.insertElement(25)
    lst.displayList()
  
    # Search for node 19
    lst.searchElement(19)
  
    # Delete node 19
    lst.deleteElement(19)
    lst.displayList()
  
main()


输出:

Successfully Inserted key 3
Successfully Inserted key 6
Successfully Inserted key 7
Successfully Inserted key 9
Successfully Inserted key 12
Successfully Inserted key 19
Successfully Inserted key 17
Successfully Inserted key 26
Successfully Inserted key 21
Successfully Inserted key 25

*****Skip List*****
Level 0: 3 6 7 9 12 17 19 21 25 26 
Level 1: 3 17 19 21 26 
Level 2: 17 19 21 
Found key: 19
Successfully deleted key 19

*****Skip List*****
Level 0: 3 6 7 9 12 17 21 25 26 
Level 1: 3 17 21 26 
Level 2: 17 21 

搜索和删除的时间复杂度相同–
时间复杂度(平均)O(log n)
时间复杂度(最差): O(n)

参考
ftp://ftp.cs.umd.edu/pub/skipLists/skiplists.pdf