通过颠倒所有回文词的出现顺序来修改句子

给定表示句子的字符串S ，任务是颠倒句子中所有回文词的顺序。

例子：

Input: S = “mom and dad went to eye hospital”
Output: eye and dad went to mom hospital
Explanation: All palindromic words present in the string are “mom”, “dad” and “eye“, in the order of their occurrence. Reversing the order of their occurrence generates the sequence {“eye”, “dad”, “mom”}. Therefore, the modified string is “eye and dad went to mom hospital”.

Input : S = “wow it is next level”
Output: level it is wow.

方法：请按照以下步骤解决问题：

• 迭代字符串S的字符，并使用split()将句子中用空格分隔的单词分开，然后将它们存储在列表中，例如lis 。
• 使用append()将所有回文词追加到一个新列表，例如newlist 函数。
• 使用reverse()函数反转此新列表。
• 遍历列表LIS和保持与newlist [I](最初，I = 0)和增量i增加1替换回文字。
• 打印修改后的句子

下面是上述方法的实现：

C++

// C++ implementation of
// the above approach
#include
using namespace std;
 
// Function to check if a
// string S is a palindrome
bool palindrome(string str)
{
    int st = 0;
    int ed = str.length() - 1;
     
    while (st < ed)
    {
        if (str[st] == str[ed])
        {
            st++;
            ed--;
        }
        else
          return false;
    }
    return true;
}
 
// Function to print the modified string
// after reversing teh order of occurrences
// of all palindromic words in the sentence
void printReverse(string sentence)
{
     
    // Stores the palindromic words
    vector newlist;
    vector lis;
     
    // Stores the words in the list
    string temp = "";
     
    for(auto x : sentence)
    {
        if (x == ' ')
        {
            lis.push_back(temp);
            temp = "";
        }
        else
            temp += x;
    }
    lis.push_back(temp);
     
    // Traversing the list
    for(auto x: lis)
    {
         
        // If current word is a palindrome
        if (palindrome(x))
         
            // Update newlist
            newlist.push_back(x);
    }
 
    // Reverse the newlist
    reverse(newlist.begin(),newlist.end());
     
    int j = 0;
     
    // Traverse the list
    for(int i = 0; i < lis.size(); i++)
    {
         
        // If current word is a palindrome
        if (palindrome(lis[i]))
        {
             
            // Update lis[i]
            lis[i] = newlist[j];
             
            // Increment j
            j = j + 1;
        }
    }
 
    // Print the updated sentence
    for(auto x: lis)
       cout << x << " ";
}
 
// Driver Code
int main()
{
    string sentence = "mom and dad went to eye hospital";
    printReverse(sentence);
}
 
// This code is contributed by bgangwar59

Python3

# Python implementation of
# the above approach
 
# Function to check if a
# string S is a palindrome
def palindrome(string):
   
    if(string == string[::-1]):
        return True
    else:
        return False
 
# Function to print the modified string
# after reversing teh order of occurrences
# of all palindromic words in the sentence
def printReverse(sentence):
   
    # Stores the palindromic words
    newlist = []
     
    # Stores the words in the list
    lis = list(sentence.split())
     
    # Traversing the list
    for i in lis:
       
        # If current word is a palindrome
        if(palindrome(i)):
           
              # Update newlist
            newlist.append(i)
 
    # Reverse the newlist
    newlist.reverse()
     
    j = 0
     
    # Traverse the list
    for i in range(len(lis)):
       
        # If current word is a palindrome
        if(palindrome(lis[i])):
           
            # Update lis[i]
            lis[i] = newlist[j]
             
            # Increment j
            j = j + 1
 
    # Print the updated sentence
    for i in lis:
        print(i, end =" ")
 
 
# Driver Code
 
sentence = "mom and dad went to eye hospital"
printReverse(sentence)

C#

// C# implementation of
// the above approach
using System;
using System.Collections.Generic;
 
class GFG{
 
// Function to check if a
// string S is a palindrome
static bool palindrome(string str)
{
    int st = 0;
    int ed = str.Length - 1;
 
    while (st < ed)
    {
        if (str[st] == str[ed])
        {
            st++;
            ed--;
        }
        else
            return false;
    }
    return true;
}
 
// Function to print the modified string
// after reversing teh order of occurrences
// of all palindromic words in the sentence
static void printReverse(string sentence)
{
     
    // Stores the palindromic words
    List newlist = new List();
    List lis = new List();
 
    // Stores the words in the list
    string temp = "";
 
    foreach(char x in sentence)
    {
        if (x == ' ')
        {
            lis.Add(temp);
            temp = "";
        }
        else
            temp += x;
    }
    lis.Add(temp);
 
    // Traversing the list
    foreach(string x in lis)
    {
 
        // If current word is a palindrome
        if (palindrome(x))
 
            // Update newlist
            newlist.Add(x);
    }
 
    // Reverse the newlist
    newlist.Reverse();
 
    int j = 0;
 
    // Traverse the list
    for(int i = 0; i < lis.Count; i++)
    {
         
        // If current word is a palindrome
        if (palindrome(lis[i]))
        {
             
            // Update lis[i]
            lis[i] = newlist[j];
 
            // Increment j
            j = j + 1;
        }
    }
 
    // Print the updated sentence
    foreach(string x in lis)
        Console.Write(x + " ");
}
 
// Driver Code
public static void Main()
{
    string sentence = "mom and dad went to eye hospital";
    printReverse(sentence);
}
}
 
// This code is contributed by ukasp

输出：

eye and dad went to mom hospital

时间复杂度： O(N)
辅助空间： O(1)