给定数字N ,任务是找到第N个六边形四边形数字。
An Hexacontatetragon number is a class of figurate numbers. It has a 64-sided polygon called Hexacontatetragon. The N-th Hexacontatetragon number count’s the 64 number of dots and all other dots are surrounding with a common sharing corner and make a pattern. The first few Hexacontatetragonol numbers are 1, 64, 189, 376, 625, 936, …
例子:
Input: N = 2
Output: 64
Explanation:
The second Hexacontatetragonol number is 64.
Input: N = 3
Output: 189
方法:第N个六边形四边形数由下式给出:
- 侧多边形的第N个项=
- 因此64边多边形的Nth项是
下面是上述方法的实现:
C++
// C++ implementation for above approach
#include
using namespace std;
// Function to Find the
// Nth Hexacontatetragon Number
int HexacontatetragonNum(int n)
{
return (62 * n * n - 60 * n) / 2;
}
// Driver Code
int main()
{
int n = 3;
cout << HexacontatetragonNum(n);
return 0;
}
Java
// Java program to find N-th
// Hexacontatetragon number
class GFG{
// Function to find the nth
// Hexacontatetragon number
static int HexacontatetragonNum(int n)
{
return (62 * n * n - 60 * n) / 2;
}
// Driver code
public static void main(String[] args)
{
int n = 3;
System.out.print(HexacontatetragonNum(n));
}
}
// This code is contributed by shubham
Python3
# Python3 implementation for above approach
# Function to Find the
# Nth Hexacontatetragon Number
def HexacontatetragonNum(n):
return (62 * n * n - 60 * n) / 2;
# Driver Code
n = 3;
print(HexacontatetragonNum(n));
# This code is contributed by Code_Mech
C#
// C# program to find N-th
// Hexacontatetragon number
using System;
class GFG{
// Function to find the nth
// Hexacontatetragon number
static int HexacontatetragonNum(int n)
{
return (62 * n * n - 60 * n) / 2;
}
// Driver code
public static void Main()
{
int n = 3;
Console.Write(HexacontatetragonNum(n));
}
}
// This code is contributed by Code_Mech
Javascript
输出:
189
参考: https : //en.wikipedia.org/wiki/Hexacontatetragon