示例:检查一个字符串是否是另外两个字符串的有效改组
class Main {
// check if result string is valid shuffle of string first and second
static boolean shuffleCheck(String first, String second, String result) {
// check length of result is same as
// sum of result of first and second
if(first.length() + second.length() != result.length()) {
return false;
}
// variables to track each character of 3 strings
int i = 0, j = 0, k = 0;
// iterate through all characters of result
while (k != result.length()) {
// check if first character of result matches with first character of first string
if (i < first.length() && first.charAt(i) == result.charAt(k))
i++;
// check if first character of result matches the first character of second string
else if (j < second.length() && second.charAt(j) == result.charAt(k))
j++;
// if the character doesn't match
else {
return false;
}
// access next character of result
k++;
}
// after accessing all characters of result
// if either first or second has some characters left
if(i < first.length() || j < second.length()) {
return false;
}
return true;
}
public static void main(String[] args) {
String first = "XY";
String second = "12";
String[] results = {"1XY2", "Y12X"};
// call the method to check if result string is
// shuffle of the string first and second
for (String result : results) {
if (shuffleCheck(first, second, result) == true) {
System.out.println(result + " is a valid shuffle of " + first + " and " + second);
}
else {
System.out.println(result + " is not a valid shuffle of " + first + " and " + second);
}
}
}
}
输出
1XY2 is a valid shuffle of XY and 12
Y12X is not a valid shuffle of XY and 12
在上面的示例中,我们有一个名为results的字符串数组。它包含两个字符串: 1XY2和Y12X 。我们正在检查这两个字符串是否是字符串 first(XY)和second(12)的有效改组。
在这里,程序说1XY2是XY和12的有效改组 。但是, Y12X不是有效的随机播放。
这是因为Y12X更改了字符串 XY的顺序。在此,在X之前使用Y。因此,作为有效的改组,应保持字符串的顺序。