Python - 字典列表中键的值限制

给定一个字典列表，编写一个Python程序来为字典列表中的每个键分配限制。（每个键都有所有键）。

例子：

Input : test_list = [{“gfg” : 4, “is” : 7, “best” : 10}, {“gfg” : 2, “is” : 5, “best” : 9}, {“gfg” : 1, “is” : 2, “best” : 6}] 
Output : {‘gfg’: [1, 4], ‘is’: [2, 7], ‘best’: [6, 10]} 
Explanation : gfg has min. value to be 1 and maximum to be 4.
 

Input : test_list = [{“gfg” : 4, “best” : 10}, {“gfg” : 2, “best” : 9}, {“gfg” : 1, “best” : 6}] 
Output : {‘gfg’: [1, 4], ‘best’: [6, 10]} 
Explanation : best has min. value to be 6 and maximum to be 10. 

方法 #1：使用max() + min() + loop + keys()

在这里，我们使用keys() 执行获取所有键的任务，并且使用min() 和max() 计算限制的最小值和最大值。所有字典的迭代都是使用循环进行的。

Python3

# Python3 code to demonstrate working of
# Value limits to keys in Dictionaries List
# Using max() + min() + loop + keys()
  
# initializing Matrix
test_list = [{"gfg": 4, "is": 7, "best": 10},
             {"gfg": 2, "is": 5, "best": 9},
             {"gfg": 1, "is": 2, "best": 6}]
  
# printing original list
print("The original list is : " + str(test_list))
  
res = dict()
  
# extraction of all keys
keys = list(test_list[0].keys())
  
for key in keys:
  
    # assigning ranges to each key
    res[key] = [min(sub[key] for sub in test_list), max(sub[key]
                                                        for sub in test_list)]
  
# printing result
print("Keys Ranges : " + str(res))

输出：

The original list is : [{‘gfg’: 4, ‘is’: 7, ‘best’: 10}, {‘gfg’: 2, ‘is’: 5, ‘best’: 9}, {‘gfg’: 1, ‘is’: 2, ‘best’: 6}]
Keys Ranges : {‘gfg’: [1, 4], ‘is’: [2, 7], ‘best’: [6, 10]}

方法 #2：使用字典理解+ min() + max() + keys()

在这种情况下，我们使用一个线性字典理解来执行迭代任务，与上述方法类似，只是一种速记。

蟒蛇3

# Python3 code to demonstrate working of
# Value limits to keys in Dictionaries List
# Using list comprehension + min() + max() + keys()
  
# initializing Matrix
test_list = [{"gfg": 4, "is": 7, "best": 10},
             {"gfg": 2, "is": 5, "best": 9},
             {"gfg": 1, "is": 2, "best": 6}]
  
# printing original list
print("The original list is : " + str(test_list))
  
# extraction of all keys
keys = list(test_list[0].keys())
  
# Dictionary comprehension used as one liner to perform task
res = {key: [min(sub[key] for sub in test_list), max(sub[key]
                                                     for sub in test_list)] for key in keys}
  
# printing result
print("Keys Ranges : " + str(res))

输出：

The original list is : [{‘gfg’: 4, ‘is’: 7, ‘best’: 10}, {‘gfg’: 2, ‘is’: 5, ‘best’: 9}, {‘gfg’: 1, ‘is’: 2, ‘best’: 6}]
Keys Ranges : {‘gfg’: [1, 4], ‘is’: [2, 7], ‘best’: [6, 10]}