带有示例的Java floor() 方法
Java.lang.Math.floor()返回小于或等于参数且等于最接近的数学整数的双精度值。
笔记:
- 如果参数是Integer ,则结果是Integer 。
- 如果参数是NaN或无穷大或正零或负零,则结果与参数相同。
public static double floor(double a)
a : the argument whose floor value is to be determined
Returns : This method returns the double value that is less than or equal
to the argument and is equal to the nearest mathematical integer.
示例:显示Java.lang.Math.floor()方法的工作。
// Java program to demonstrate working
// of java.lang.Math.floor() method
import java.lang.Math;
class Gfg {
// driver code
public static void main(String args[])
{
double a = 4.3;
double b = 1.0 / 0;
double c = 0.0;
double d = -0.0;
double e = -2.3;
System.out.println(Math.floor(a));
// Input Infinity, Output Infinity
System.out.println(Math.floor(b));
// Input Positive Zero, Output Positive Zero
System.out.println(Math.floor(c));
// Input Negative Zero, Output Negative Zero
System.out.println(Math.floor(d));
// Input -2.3, Output -3.0
// Nearest Integer(-3.0) < less than (-2.3)
System.out.println(Math.floor(e));
}
}
输出:
4.0
Infinity
0.0
-0.0
-3.0