给定时间点的Unix时间戳记T (以秒为单位),任务是将其转换为人类可读的格式(DD / MM / YYYY HH:MM:SS)
例子:
Input: T = 1595497956
Output:23/7/2020 9:52:36
Explanation:In unix time T have 1595497956 seconds, So it makes total 50 years, 7 months, 23 days and 9 hours, 52 minutes and 36 second.
Input: T = 345234235
Output:9/12/1980 18:23:55
方法:
- 将给定的秒数除以一天中的秒数即可将其转换为天数(86400),然后存储剩余的秒数。
- 由于我们计算的是自1970年1月1日以来的天数。因此,在计算当前年份时要牢记leap年的概念。从1970年开始。如果年份是a年,则从天中减去366,否则减去365。将年份增加1。
- 重复步骤2,直到天数少于365(不能构成一年)。
- 将1加到剩余天数(计算年份后的额外天数),因为剩余天数会给我们直到前一天的天数,并且我们必须包括当前日期以进行DATE和MONTH计算。
- 将月份数增加1,并从额外的天数中减去月份的天数(请记住,February年2月将有29天,否则将有28天)。
- 重复步骤5,直到从多余的天中减去一个月中的某几天将得到否定的结果。
- 如果多余的天数大于零,则将月份增加1。
- 现在,利用从第1步开始的额外时间。
- 用多余的时间除以3600来计算小时,用剩余的秒除以60来计算分钟,而秒将是剩余的秒。
下面是上述方法的实现:
C++
// C++ program for the above approach
// Unix time is in seconds and
// Humar Readable Format:
// DATE:MONTH:YEAR:HOUR:MINUTES:SECONDS,
// Start of unix time:01 Jan 1970, 00:00:00
#include
using namespace std;
// Function to convert unix time to
// Human readable format
string
unixTimeToHumanReadable(long int seconds)
{
// Save the time in Human
// readable format
string ans = "";
// Number of days in month
// in normal year
int daysOfMonth[] = { 31, 28, 31, 30, 31, 30,
31, 31, 30, 31, 30, 31 };
long int currYear, daysTillNow, extraTime,
extraDays, index, date, month, hours,
minutes, secondss, flag = 0;
// Calculate total days unix time T
daysTillNow = seconds / (24 * 60 * 60);
extraTime = seconds % (24 * 60 * 60);
currYear = 1970;
// Calculating currrent year
while (daysTillNow >= 365) {
if (currYear % 400 == 0
|| (currYear % 4 == 0
&& currYear % 100 != 0)) {
daysTillNow -= 366;
}
else {
daysTillNow -= 365;
}
currYear += 1;
}
// Updating extradays because it
// will give days till previous day
// and we have include current day
extraDays = daysTillNow + 1;
if (currYear % 400 == 0
|| (currYear % 4 == 0
&& currYear % 100 != 0))
flag = 1;
// Calculating MONTH and DATE
month = 0, index = 0;
if (flag == 1) {
while (true) {
if (index == 1) {
if (extraDays - 29 < 0)
break;
month += 1;
extraDays -= 29;
}
else {
if (extraDays
- daysOfMonth[index]
< 0) {
break;
}
month += 1;
extraDays -= daysOfMonth[index];
}
index += 1;
}
}
else {
while (true) {
if (extraDays
- daysOfMonth[index]
< 0) {
break;
}
month += 1;
extraDays -= daysOfMonth[index];
index += 1;
}
}
// Current Month
if (extraDays > 0) {
month += 1;
date = extraDays;
}
else {
if (month == 2 && flag == 1)
date = 29;
else {
date = daysOfMonth[month - 1];
}
}
// Calculating HH:MM:YYYY
hours = extraTime / 3600;
minutes = (extraTime % 3600) / 60;
secondss = (extraTime % 3600) % 60;
ans += to_string(date);
ans += "/";
ans += to_string(month);
ans += "/";
ans += to_string(currYear);
ans += " ";
ans += to_string(hours);
ans += ":";
ans += to_string(minutes);
ans += ":";
ans += to_string(secondss);
// Return the time
return ans;
}
// Driver Code
int main()
{
// Given unix time
long int T = 1595497956;
// Function call to convert unix
// time to human read able
string ans = unixTimeToHumanReadable(T);
// Print time in format
// DD:MM:YYYY:HH:MM:SS
cout << ans << "\n";
return 0;
}
Java
// Java program for the above approach
// Unix time is in seconds and
// Humar Readable Format:
// DATE:MONTH:YEAR:HOUR:MINUTES:SECONDS,
// Start of unix time:01 Jan 1970, 00:00:00
import java.util.*;
class GFG{
// Function to convert unix time to
// Human readable format
static String unixTimeToHumanReadable(int seconds)
{
// Save the time in Human
// readable format
String ans = "";
// Number of days in month
// in normal year
int daysOfMonth[] = { 31, 28, 31, 30, 31, 30,
31, 31, 30, 31, 30, 31 };
int currYear, daysTillNow, extraTime,
extraDays, index, date, month, hours,
minutes, secondss, flag = 0;
// Calculate total days unix time T
daysTillNow = seconds / (24 * 60 * 60);
extraTime = seconds % (24 * 60 * 60);
currYear = 1970;
// Calculating currrent year
while (daysTillNow >= 365)
{
if (currYear % 400 == 0 ||
(currYear % 4 == 0 &&
currYear % 100 != 0))
{
daysTillNow -= 366;
}
else
{
daysTillNow -= 365;
}
currYear += 1;
}
// Updating extradays because it
// will give days till previous day
// and we have include current day
extraDays = daysTillNow + 1;
if (currYear % 400 == 0 ||
(currYear % 4 == 0 &&
currYear % 100 != 0))
flag = 1;
// Calculating MONTH and DATE
month = 0; index = 0;
if (flag == 1)
{
while (true)
{
if (index == 1)
{
if (extraDays - 29 < 0)
break;
month += 1;
extraDays -= 29;
}
else
{
if (extraDays -
daysOfMonth[index] < 0)
{
break;
}
month += 1;
extraDays -= daysOfMonth[index];
}
index += 1;
}
}
else
{
while (true)
{
if (extraDays - daysOfMonth[index] < 0)
{
break;
}
month += 1;
extraDays -= daysOfMonth[index];
index += 1;
}
}
// Current Month
if (extraDays > 0)
{
month += 1;
date = extraDays;
}
else
{
if (month == 2 && flag == 1)
date = 29;
else
{
date = daysOfMonth[month - 1];
}
}
// Calculating HH:MM:YYYY
hours = extraTime / 3600;
minutes = (extraTime % 3600) / 60;
secondss = (extraTime % 3600) % 60;
ans += String.valueOf(date);
ans += "/";
ans += String.valueOf(month);
ans += "/";
ans += String.valueOf(currYear);
ans += " ";
ans += String.valueOf(hours);
ans += ":";
ans += String.valueOf(minutes);
ans += ":";
ans += String.valueOf(secondss);
// Return the time
return ans;
}
// Driver Code
public static void main(String[] args)
{
// Given unix time
int T = 1595497956;
// Function call to convert unix
// time to human read able
String ans = unixTimeToHumanReadable(T);
// Print time in format
// DD:MM:YYYY:HH:MM:SS
System.out.print(ans + "\n");
}
}
// This code is contributed by 29AjayKumar
Python3
# Python3 program for the above approach
# Unix time is in seconds and
# Humar Readable Format:
# DATE:MONTH:YEAR:HOUR:MINUTES:SECONDS,
# Start of unix time:01 Jan 1970, 00:00:00
# Function to convert unix time to
# Human readable format
def unixTimeToHumanReadable(seconds):
# Save the time in Human
# readable format
ans = ""
# Number of days in month
# in normal year
daysOfMonth = [ 31, 28, 31, 30, 31, 30,
31, 31, 30, 31, 30, 31 ]
(currYear, daysTillNow, extraTime,
extraDays, index, date, month, hours,
minutes, secondss, flag) = ( 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0 )
# Calculate total days unix time T
daysTillNow = seconds // (24 * 60 * 60)
extraTime = seconds % (24 * 60 * 60)
currYear = 1970
# Calculating currrent year
while (daysTillNow >= 365):
if (currYear % 400 == 0 or
(currYear % 4 == 0 and
currYear % 100 != 0)):
daysTillNow -= 366
else:
daysTillNow -= 365
currYear += 1
# Updating extradays because it
# will give days till previous day
# and we have include current day
extraDays = daysTillNow + 1
if (currYear % 400 == 0 or
(currYear % 4 == 0 and
currYear % 100 != 0)):
flag = 1
# Calculating MONTH and DATE
month = 0
index = 0
if (flag == 1):
while (True):
if (index == 1):
if (extraDays - 29 < 0):
break
month += 1
extraDays -= 29
else:
if (extraDays - daysOfMonth[index] < 0):
break
month += 1
extraDays -= daysOfMonth[index]
index += 1
else:
while (True):
if (extraDays - daysOfMonth[index] < 0):
break
month += 1
extraDays -= daysOfMonth[index]
index += 1
# Current Month
if (extraDays > 0):
month += 1
date = extraDays
else:
if (month == 2 and flag == 1):
date = 29
else:
date = daysOfMonth[month - 1]
# Calculating HH:MM:YYYY
hours = extraTime // 3600
minutes = (extraTime % 3600) // 60
secondss = (extraTime % 3600) % 60
ans += str(date)
ans += "/"
ans += str(month)
ans += "/"
ans += str(currYear)
ans += " "
ans += str(hours)
ans += ":"
ans += str(minutes)
ans += ":"
ans += str(secondss)
# Return the time
return ans
# Driver code
if __name__=="__main__":
# Given unix time
T = 1595497956
# Function call to convert unix
# time to human read able
ans = unixTimeToHumanReadable(T)
# Print time in format
# DD:MM:YYYY:HH:MM:SS
print(ans)
# This code is contributed by rutvik_56
C#
// C# program for the above approach
// Unix time is in seconds and
// Humar Readable Format:
// DATE:MONTH:YEAR:HOUR:MINUTES:SECONDS,
// Start of unix time:01 Jan 1970, 00:00:00
using System;
class GFG{
// Function to convert unix time to
// Human readable format
static String unixTimeToHumanReadable(int seconds)
{
// Save the time in Human
// readable format
String ans = "";
// Number of days in month
// in normal year
int []daysOfMonth = { 31, 28, 31, 30, 31, 30,
31, 31, 30, 31, 30, 31 };
int currYear, daysTillNow, extraTime,
extraDays, index, date, month, hours,
minutes, secondss, flag = 0;
// Calculate total days unix time T
daysTillNow = seconds / (24 * 60 * 60);
extraTime = seconds % (24 * 60 * 60);
currYear = 1970;
// Calculating currrent year
while (daysTillNow >= 365)
{
if (currYear % 400 == 0 ||
(currYear % 4 == 0 &&
currYear % 100 != 0))
{
daysTillNow -= 366;
}
else
{
daysTillNow -= 365;
}
currYear += 1;
}
// Updating extradays because it
// will give days till previous day
// and we have include current day
extraDays = daysTillNow + 1;
if (currYear % 400 == 0 ||
(currYear % 4 == 0 &&
currYear % 100 != 0))
flag = 1;
// Calculating MONTH and DATE
month = 0; index = 0;
if (flag == 1)
{
while (true)
{
if (index == 1)
{
if (extraDays - 29 < 0)
break;
month += 1;
extraDays -= 29;
}
else
{
if (extraDays -
daysOfMonth[index] < 0)
{
break;
}
month += 1;
extraDays -= daysOfMonth[index];
}
index += 1;
}
}
else
{
while (true)
{
if (extraDays - daysOfMonth[index] < 0)
{
break;
}
month += 1;
extraDays -= daysOfMonth[index];
index += 1;
}
}
// Current Month
if (extraDays > 0)
{
month += 1;
date = extraDays;
}
else
{
if (month == 2 && flag == 1)
date = 29;
else
{
date = daysOfMonth[month - 1];
}
}
// Calculating HH:MM:YYYY
hours = extraTime / 3600;
minutes = (extraTime % 3600) / 60;
secondss = (extraTime % 3600) % 60;
ans += String.Join("", date);
ans += "/";
ans += String.Join("", month);
ans += "/";
ans += String.Join("", currYear);
ans += " ";
ans += String.Join("", hours);
ans += ":";
ans += String.Join("", minutes);
ans += ":";
ans += String.Join("", secondss);
// Return the time
return ans;
}
// Driver Code
public static void Main(String[] args)
{
// Given unix time
int T = 1595497956;
// Function call to convert unix
// time to human read able
String ans = unixTimeToHumanReadable(T);
// Print time in format
// DD:MM:YYYY:HH:MM:SS
Console.Write(ans + "\n");
}
}
// This code is contributed by 29AjayKumar
输出:
23/7/2020 9:52:36
要从最佳影片策划和实践问题去学习,检查了C++基础课程为基础,以先进的C++和C++ STL课程基础加上STL。