将一个字符串分成N等份

难度级别：新手
题：
编写一个程序来打印给定字符串的 N 个相等部分。
解决方案：
1) 使用字符串函数strlen() 获取字符串的大小（存在于字符串.h 中）
2）获取零件的尺寸。

part_size = string_length/n 

3) 循环输入字符串。在循环中，如果 index 变为 part_size 的倍数，则放置一个部分分隔符（“\n”）
执行：

C++

// C++ program to divide a string
// in n equal parts
#include 
#include 
 
using namespace std;
 
class gfg {
 
    // Function to print n equal parts of str
public:
    void divideString(char str[], int n)
    {
 
        int str_size = strlen(str);
        int i;
        int part_size;
 
        // Check if string can be divided in
        // n equal parts
        if (str_size % n != 0) {
            cout << "Invalid Input: String size";
            cout << " is not divisible by n";
            return;
        }
 
        // Calculate the size of parts to
        // find the division points
        part_size = str_size / n;
        for (i = 0; i < str_size; i++) {
            if (i % part_size == 0)
                cout << endl;
            cout << str[i];
        }
    }
};
 
// Driver code
int main()
{
    gfg g;
 
    // length od string is 28
    char str[] = "a_simple_divide_string_quest";
 
    // Print 4 equal parts of the string
    g.divideString(str, 4);
    return 0;
}
 
// This code is contributed by SoM15242

C

// C program to divide a string
// in n equal parts
#include 
#include 
 
// Function to print n equal parts of str
void divideString(char* str, int n)
{
    int str_size = strlen(str);
    int i;
    int part_size;
 
    // Check if string can be divided in
    // n equal parts
    if (str_size % n != 0) {
        printf("Invalid Input: String size");
        printf(" is not divisible by n");
        return;
    }
 
    // Calculate the size of parts to
    // find the division points
    part_size = str_size / n;
    for (i = 0; i < str_size; i++) {
        if (i % part_size == 0)
            printf("\n");
        printf("%c", str[i]);
    }
}
 
int main()
{
    // length od string is 28
    char* str = "a_simple_divide_string_quest";
 
    // Print 4 equal parts of the string
    divideString(str, 4);
 
    getchar();
    return 0;
}

Java

// Java program to divide a string
// in n equal parts
 
class GFG {
    // Method to print n equal parts of str
    static void divideString(String str, int n)
    {
        int str_size = str.length();
        int part_size;
 
        // Check if string can be divided in
        // n equal parts
        if (str_size % n != 0) {
            System.out.println("Invalid Input: String size"
                               + "is not divisible by n");
            return;
        }
 
        // Calculate the size of parts to find
        // the division points
        part_size = str_size / n;
 
        for (int i = 0; i < str_size; i++) {
            if (i % part_size == 0)
                System.out.println();
            System.out.print(str.charAt(i));
        }
    }
 
    // Driver Code
    public static void main(String[] args)
    {
        // length od string is 28
        String str = "a_simple_divide_string_quest";
 
        // Print 4 equal parts of the string
        divideString(str, 4);
    }
}

Python3

# Python program to print n equal parts of string
 
# Function to print n equal parts of string
 
 
def divideString(string, n):
    str_size = len(string)
 
    # Check if string can be divided in n equal parts
    if str_size % n != 0:
        print ("Invalid Input: String size is not divisible by n")
        return
 
    # Calculate the size of parts to find the division points
    part_size = str_size/n
    k = 0
    for i in string:
        if k % part_size == 0:
            print ()
        print (i,end='')
        k += 1
 
 
# Driver program to test the above function
# Length of string is 28
string = "a_simple_divide_string_quest"
 
# Print 4 equal parts of the string
divideString(string, 4)
 
# This code is contributed by Bhavya Jain

C#

// C# program to divide a string
// in n equal parts
using System;
 
class GFG {
 
    // Method to print n
    // equal parts of str
    static void divideString(String str, int n)
    {
        int str_size = str.Length;
        int part_size;
 
        // Check if string
        // can be divided in
        // n equal parts
        if (str_size % n != 0) {
            Console.Write("Invalid Input: String size"
                          + "is not divisible by n");
            return;
        }
 
        // Calculate the size
        // of parts to find
        // the division points
        part_size = str_size / n;
 
        for (int i = 0; i < str_size; i++) {
            if (i % part_size == 0)
                Console.WriteLine();
            Console.Write(str[i]);
        }
    }
 
    // Driver Code
    static void Main()
    {
 
        // length od string is 28
        String str = "a_simple_divide_string_quest";
 
        // Print 4 equal parts of the string
        divideString(str, 4);
    }
}
 
// This code is contributed by Anuj_67

Javascript

    // Javascript program to divide a string
    // in n equal parts
     
    // Method to print n
    // equal parts of str
    function divideString(str, n)
    {
        let str_size = str.length;
        let part_size;
 
        // Check if string
        // can be divided in
        // n equal parts
        if (str_size % n != 0)
        {
            document.write("Invalid Input: String size" +
                          "is not divisible by n");
            return;
        }
 
        // Calculate the size
        // of parts to find
        // the division points
        part_size = parseInt(str_size / n, 10);
 
        for (let i = 0; i< str_size; i++)
        {
            if(i % part_size == 0)
                document.write("</br>");
            document.write(str[i]);
        }
    }
       
    // length od string is 28
    let str = "a_simple_divide_string_quest";
 
    // Print 4 equal parts of the string
    divideString(str, 4);
     
    // This code is contributed by rameshtravel07

输出

a_simpl
e_divid
e_strin
g_quest

在上述解决方案中，仅打印字符串的 n 个相等部分。如果我们想要存储单个部分，我们需要为所有 N 个部分分配 part_size + 1 内存（字符串终止字符'\0' 额外分配 1 个）并将这些部分的地址存储在字符指针数组中。

另一种方法：在 C++ 中使用 STL

C++

#include 
 
using namespace std;
 
void divide(string str, int n)
{
 
    if (str.length() % n != 0) {
        cout << "Invalid Input: String size";
        cout << " is not divisible by n";
        return;
    }
 
    int parts = str.length() / n;
    int start = 0;
 
    while (start < str.length()) {
        cout << str.substr(start, parts) << endl;
        start += parts;
        // if(start < str.length()) cout << endl; to ignore
        // final new line
    }
}
 
int main()
{
    string str = "a_simple_divide_string_quest";
    divide(str, 4);
}
 
//Contributed By Jagadeesh

Java

import java.util.*;
 
class GFG {
 
    static void divide(String str, int n) {
 
        if (str.length() % n != 0) {
            System.out.print("Invalid Input: String size");
            System.out.print(" is not divisible by n");
            return;
        }
 
        int parts = str.length() / n;
        int start = 0;
        int t = parts;
        while (start < str.length()) {
            String temp = new String(str);
 
            System.out.print(temp.substring(start, parts) + "\n");
            start = parts;
            parts += t;
            // if(start < str.length()) System.out.println(); to ignore
            // final new line
        }
    }
 
  // Driver code
    public static void main(String[] args) {
        String str = "a_simple_divide_String_quest";
        divide(str, 4);
    }
}
 
// This code is contributed by umadevi9616

输出

a_simpl
e_divid
e_strin
g_quest

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