Python – 最大可用值字典
给定字典列表和列表，从列表中提取包含最大可用键值的所有字典。
Input : test_list [{“Gfg” : 6, “is” : 9, “best” : 10},
{“Gfg” : 8, “is” : 11, “best” : 19},
{“Gfg” : 2, “is” : 16, “best” : 10}], K = “best”, arg_list = [10, 7, 6, 12]
Output : [{‘Gfg’: 6, ‘is’: 9, ‘best’: 10}, {‘Gfg’: 2, ‘is’: 16, ‘best’: 10}]
Explanation : Maximum available value of “best” is 19, but not present in list, hence next max. is 10, all dictionaries corresponding are returned.
Input : test_list [{“Gfg” : 6, “is” : 9, “best” : 10},
{“Gfg” : 8, “is” : 11, “best” : 19}], K = “Gfg”, arg_list = [10, 7, 6, 12]
Output : [{‘Gfg’: 6, ‘is’: 9, ‘best’: 10}]
Explanation : Maximum value present in this case is 6, hence returned.
方法#1：使用循环
这是可以解决此问题的粗暴方式。在此，第一个最大值是从字典值中获得的，它也存在于提供的列表中。发布所有具有该值的字典都已提取。
Python3
# Python3 code to demonstrate working of
# Maximum available value Dictionaries
# Using loop
# initializing lists
test_list = [{"Gfg" : 6, "is" : 9, "best" : 10},
{"Gfg" : 8, "is" : 11, "best" : 19},
{"Gfg" : 2, "is" : 16, "best" : 10},
{"Gfg" : 12, "is" : 1, "best" : 8},
{"Gfg" : 22, "is" : 6, "best" : 8}]
# printing original list
print("The original list : " + str(test_list))
# initializing K
K = "best"
# initializing list
arg_list = [10, 7, 6, 12]
# extracting value to find from dictionary
# corresponding to key
max_ele = 0
for sub in test_list:
if sub[K] in arg_list:
# maximum of all possible present for a key
max_ele = max(sub[K], max_ele)
# extracting dictionary with maximum and present value of key
res = [sub for sub in test_list if sub[K] == max_ele]
# printing result
print("The extracted dictionaries : " + str(res))The original list : [{‘Gfg’: 6, ‘is’: 9, ‘best’: 10}, {‘Gfg’: 8, ‘is’: 11, ‘best’: 19}, {‘Gfg’: 2, ‘is’: 16, ‘best’: 10}, {‘Gfg’: 12, ‘is’: 1, ‘best’: 8}, {‘Gfg’: 22, ‘is’: 6, ‘best’: 8}]
The extracted dictionaries : [{‘Gfg’: 6, ‘is’: 9, ‘best’: 10}, {‘Gfg’: 2, ‘is’: 16, ‘best’: 10}]