给定大小为N的整数arr数组,任务是通过从给定数组arr中精确选择K(≤N)个整数来找到表达式的最小值。假设如果选择的元素存储在数组B (B 1 ,B 2 ,B 3 …..B k )中,则表达式的值为:
例子:
Input : arr[] = {2, 0, 9, 5}, k = 2
Output : 8
Let say, choosen elements are {2, 0}, then x = 8, which is minimum possible
Input : arr[] = {4, 21, 5, 3, 8}, k = 3
Output : 200
方法 :
上面的表达式可以简化为:
因此,我们要做的就是从数组中选择k个最小的元素并求解表达式。
下面是上述方法的实现:
C++
// CPP program to find the minimum possible of the expression
// by choosing exactly K(? N) integers form given array arr
#include
using namespace std;
// Function to find the minimum possible of the expression
// by choosing exactly K(? N) integers form given array arr
int minimumValue(int arr[], int n, int k)
{
// Sorting the array for least k element selection
sort(arr, arr + n);
int answer = 0;
// Select first k elements from sorted array
for (int i = 0; i < k; i++)
answer += arr[i] * arr[i];
// Return value of solved expression
return answer * (2 * k - 2);
}
// Driver code
int main()
{
int arr[] = { 4, 21, 5, 3, 8 }, k = 3;
int n = sizeof(arr) / sizeof(arr[0]);
// Function call
cout << minimumValue(arr, n, k);
return 0;
}
Java
// JAVA program to find the minimum possible of the expression
// by choosing exactly K(? N) integers form given array arr
import java.util.*;
class GFG{
// Function to find the minimum possible of the expression
// by choosing exactly K(? N) integers form given array arr
static int minimumValue(int arr[], int n, int k)
{
// Sorting the array for least k element selection
Arrays.sort(arr);
int answer = 0;
// Select first k elements from sorted array
for (int i = 0; i < k; i++)
answer += arr[i] * arr[i];
// Return value of solved expression
return answer * (2 * k - 2);
}
// Driver code
public static void main(String[] args)
{
int arr[] = { 4, 21, 5, 3, 8 }, k = 3;
int n = arr.length;
// Function call
System.out.print(minimumValue(arr, n, k));
}
}
// This code is contributed by Rajput-Ji
Python3
# Python program to find the minimum
# possible of the expression by choosing
# exactly K(? N) integers form given array arr
# Function to find the minimum
# possible of the expression by
# choosing exactly K(? N) integers
# form given array arr
def minimumValue(arr, n, k):
# Sorting the array for least k element selection
arr.sort();
answer = 0;
# Select first k elements from sorted array
for i in range(k):
answer += arr[i] * arr[i];
# Return value of solved expression
return answer * (2 * k - 2);
# Driver code
if __name__ == '__main__':
arr = [ 4, 21, 5, 3, 8 ];
k = 3;
n = len(arr);
# Function call
print(minimumValue(arr, n, k));
# This code is contributed by Rajput-Ji
C#
// C# program to find the minimum possible of the expression
// by choosing exactly K(? N) integers form given array arr
using System;
class GFG{
// Function to find the minimum possible of the expression
// by choosing exactly K(? N) integers form given array arr
static int minimumValue(int []arr, int n, int k)
{
// Sorting the array for least k element selection
Array.Sort(arr);
int answer = 0;
// Select first k elements from sorted array
for (int i = 0; i < k; i++)
answer += arr[i] * arr[i];
// Return value of solved expression
return answer * (2 * k - 2);
}
// Driver code
public static void Main(String[] args)
{
int []arr = { 4, 21, 5, 3, 8 };
int k = 3;
int n = arr.Length;
// Function call
Console.Write(minimumValue(arr, n, k));
}
}
// This code is contributed by 29AjayKumar
Javascript
输出:
200