程序转换字符

给定一个整数N。任务是将数字转换为字符。
例子：

Input: N = 74254 
Output: Seven four two five four
Input: N = 23 
Output: Two three 
 

一种有效的方法：

1. 倒数。
2. 从右到左遍历反转的数字。
3. 通过使用模数提取最后一位数字，然后使用切换大小写来获取相应的单词。
4. 迭代时，将数字除以10。

C++

// C++ program to convert number in characters
#include
using namespace std;
void NumbertoCharacter(int n)
{
    int rev = 0, r = 0;
 
    // To calculate the reverse of the number
    while (n > 0) {
 
        // The remainder will give the last digit of the number
        r = n % 10;
        rev = rev * 10 + r;
        n = n / 10;
    }
 
    while (rev > 0) {
        // Extract the first digit of the reversed number
        r = rev % 10;
 
        // Match it with switch case
        switch (r) {
        case 1:
            cout << "one ";
            break;
        case 2:
            cout << "two ";
            break;
        case 3:
            cout << "three ";
            break;
        case 4:
            cout << "four ";
            break;
        case 5:
            cout << "five ";
            break;
        case 6:
            cout << "six ";
            break;
        case 7:
            cout << "seven ";
            break;
        case 8:
            cout << "eight ";
            break;
        case 9:
            cout << "nine ";
            break;
        case 0:
            cout << "zero ";
            break;
        default:
            cout << "UnValid ";
            break;
        }
 
        // Divide the number by 10 to get the next number
        rev = rev / 10;
    }
}
// Driver code
#include 
int main()
{
    int n = 12345;
    NumbertoCharacter(n);
    return 0;
}

Java

// Java program to convert number in characters
class GFG{
     
static void NumbertoCharacter(int n)
{
    int rev = 0, r = 0;
 
    // To calculate the reverse of the number
    while (n > 0)
    {
 
        // The remainder will give
        // the last digit of the number
        r = n % 10;
        rev = rev * 10 + r;
        n = n / 10;
    }
     
    while (rev > 0)
    {
 
        // Extract the first digit
        // of the reversed number
        r = rev % 10;
 
        // Match it with switch case
        switch (r)
        {
        case 1:
            System.out.print("one ");
            break;
        case 2:
            System.out.print("two ");
            break;
        case 3:
            System.out.print("three ");
            break;
        case 4:
            System.out.print("four ");
            break;
        case 5:
            System.out.print("five ");
            break;
        case 6:
            System.out.print("six ");
            break;
        case 7:
            System.out.print("seven ");
            break;
        case 8:
            System.out.print("eight ");
            break;
        case 9:
            System.out.print("nine ");
            break;
        case 0:
            System.out.print("zero ");
            break;
        default:
            System.out.print("UnValid ");
            break;
        }
 
        // Divide the number by 10
        // to get the next number
        rev = rev / 10;
    }
}
 
// Driver code
public static void main(String[] args)
{
    int n = 12345;
    NumbertoCharacter(n);
}
}
 
// This code is contributed by Amit Katiyar

Python3

# Python3 program to convert
# number in characters
def NumbertoCharacter(n):
    rev = 0; r = 0;
 
    # To calculate the
    # reverse of the number
    while (n > 0):
 
        # The remainder will give
        # the last digit of the number
        r = n % 10;
        rev = rev * 10 + r;
        n = n // 10;   
 
    while (rev > 0):
 
        # Extract the first digit
        # of the reversed number
        r = rev % 10;
 
        # Match it with switch case
        switcher = {
                0 : "zero ",
                1 : "one ",
                2 : "two ",
                3 : "three ",
                4 : "four ",
                5 : "five ",
                6 : "six ",
                7 : "seven ",
                8 : "eight ",
                9 : "nine "
        }
        print( switcher.get(r, "UnValid"),
               end = " ") ;       
 
        # Divide the number by 10
        # to get the next number
        rev = rev // 10;
 
# Driver code
if __name__ == '__main__':
    n = 12345;
    NumbertoCharacter(n);
 
# This code is contributed by gauravrajput1

C#

// C# program to convert number in characters
using System;
 
class GFG{
     
static void NumbertoCharacter(int n)
{
    int rev = 0, r = 0;
 
    // To calculate the reverse
    // of the number
    while (n > 0)
    {
         
        // The remainder will give
        // the last digit of the number
        r = n % 10;
        rev = rev * 10 + r;
        n = n / 10;
    }
     
    while (rev > 0)
    {
 
        // Extract the first digit
        // of the reversed number
        r = rev % 10;
 
        // Match it with switch case
        switch (r)
        {
            case 1:
                Console.Write("one ");
                break;
            case 2:
                Console.Write("two ");
                break;
            case 3:
                Console.Write("three ");
                break;
            case 4:
                Console.Write("four ");
                break;
            case 5:
                Console.Write("five ");
                break;
            case 6:
                Console.Write("six ");
                break;
            case 7:
                Console.Write("seven ");
                break;
            case 8:
                Console.Write("eight ");
                break;
            case 9:
                Console.Write("nine ");
                break;
            case 0:
                Console.Write("zero ");
                break;
            default:
                Console.Write("UnValid ");
                break;
        }
 
        // Divide the number by 10
        // to get the next number
        rev = rev / 10;
    }
}
 
// Driver code
public static void Main(String[] args)
{
    int n = 12345;
     
    NumbertoCharacter(n);
}
}
 
// This code is contributed by sapnasingh4991

输出：

one two three four five

时间复杂度： O(k)
k是数字的长度。
空间复杂度： O(1)