Python - K 大于 N 的连续范围

给定一个元素列表，任务是编写一个Python程序来获取所有 K 大于 N 的范围。

Input : [2, 6, 6, 6, 6, 5, 4, 6, 6, 8, 4, 6, 6, 6, 2, 6], K = 6, N = 3

Output : [(1, 4), (11, 13)]

Explanation : 6 is consecutive from index 1 to 4, hence 1-4 in result. 7-8 also has 6, but its less than 3 size range, hence not included in result.

Input : [2, 1, 1, 1, 1, 5, 4, 1, 1], K = 1, N = 3

Output : [(1, 4)]

Explanation : 1 is consecutive from index 1 to 4, hence 1-4 in result. 7-8 also has 1, but its less than 3 size range, hence not included in result.

方法#1：使用循环

在这种情况下，跟踪 K 的每次出现，并使用嵌套循环来获取范围的大小。如果范围大小大于 N，则将范围记录在结果中。

Python3

# Python3 code to demonstrate working of
# Consecutive Ranges of K greater than N
# Using loop
  
# initializing list
test_list = [2, 6, 6, 6, 6, 5, 4, 6, 
             6, 8, 4, 6, 6, 6, 2, 6]
  
# printing original list
print("The original list is : " + str(test_list))
  
# initializing K
K = 6
  
# initializing N
N = 3
  
res = []
strt, end = 0, 0
prev = 1
for idx, ele in enumerate(test_list):
  
    # if ele K assign end
    if ele == K:
        end = idx
  
        # if prev ele not K, reassign start
        if prev != K:     # previous item one
            strt = idx
    else:
  
        # if range is greater than N, append to result
        if prev == K and end - strt + 1 >= N:
            res.append((strt, end))
    prev = ele
  
# printing result
print("The extracted ranges : " + str(res))

输出：

The original list is : [2, 6, 6, 6, 6, 5, 4, 6, 6, 8, 4, 6, 6, 6, 2, 6]

The extracted ranges : [(1, 4), (11, 13)]

方法#2：使用enumerate() + zip() +列表切片+列表理解

在这种情况下，K 的所有结束和开始对都分别与前一个和下一个元素一起提取。然后检查对索引是否具有所需的范围以添加到列表中的结果。

蟒蛇3

# Python3 code to demonstrate working of
# Consecutive Ranges of K greater than N
# Using enumerate() + zip() + list slice + list comprehension
  
# initializing list
test_list = [2, 6, 6, 6, 6, 5, 4, 6, 
             6, 8, 4, 6, 6, 6, 2, 6]
  
# printing original list
print("The original list is : " + str(test_list))
  
# initializing K
K = 6
  
# initializing N
N = 3
  
# getting break pairs indices
brk_pairs = [idx for idx, (x, y) in enumerate(
    zip(test_list, test_list[1:]), 
  1) if (x == K) != (y == K)]
  
# The ranges are checked for size required
res = [(idx, ele - 1) for idx, ele in zip([K] + brk_pairs, 
                                          brk_pairs + [len(test_list)])
       if ele - idx >= N and test_list[idx] == K]
  
# printing result
print("The extracted ranges : " + str(res))

输出：

The original list is : [2, 6, 6, 6, 6, 5, 4, 6, 6, 8, 4, 6, 6, 6, 2, 6]

The extracted ranges : [(1, 4), (11, 13)]